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Please i need help whats 1/5x - 2 = 4

Orlov [11]

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$\frac{1}{5} x - 2= 4 \\$

Add sides 2

$\frac{1}{5} x - 2 + 2 = 4 + 2 \\$

$\frac{1}{5} x = 6 \\$

Multiply sides by 5

$5 \times \frac{1}{5} x = 5 \times 6 \\$

$x = 30$

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$\frac{1}{5x} - 2 = 4 \\$

Add sides 2

$\frac{1}{5x} - 2 + 2 = 4 + 2 \\$

$\frac{1}{5x} = 6 \\$

Inverse both sides

$5x = \frac{1}{6} \\$

Divide sides by 5

$\frac{5x}{5} = \frac{1}{6} \div 5 \\$

$x = \frac{1}{6} \times \frac{1}{5} \\$

$x = \frac{1}{30} \\$

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3 0

3 years ago

Read 2 more answers

What is the estimate for each sum or difference of 2 1/8 -5/7

dsp73

2 1/8 estimate to 2
5/7 estimate to 1.

2-1=1

4 0

3 years ago

Add the following: 13 + (-6)

marshall27 [118]

Answer:

+ × - = -

The answer is 7

Step-by-step explanation:

13 + (-6)

13 - 6

7

8 0

3 years ago

Read 2 more answers

The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes

devlian [24]

Answer:

(a) There is no evidence to support the claim that the two machines produce rods with different mean diameters.

P-value is 0.818

(b) 95% confidence interval for the difference in mean rod diameter is (-0.17, 0.27).

This interval shows that the difference in mean is between -0.17 and 0.27.

Step-by-step explanation:

(a) Null hypothesis: The two machines produce rods with the same mean diameter.

Alternate hypothesis: The two machines produce rods with different mean diameter.

Machine 1

mean = 8.73

variance = 0.35

n1 = 15

Machine 2

mean = 8.68

variance = 0.4

n2 = 17

pooled variance = [(15-1)0.35 + (17-1)0.4] ÷ (15+17-2) = 11.3 ÷ 30 = 0.38

Test statistic (t) = (8.73 - 8.68) ÷ sqrt[0.38(1/15 + 1/17)] = 0.05 ÷ 0.218 = 0.23

degree of freedom = n1+n2-2 = 15+17-2 = 30

Significance level = 0.05 = 5%

Critical values corresponding to 30 degrees of freedom and 5% significance level are -2.042 and 2.042.

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.23 falls within the region bounded by the critical values -2.042 and 2.042.

There is no evidence to support the claim that the two machines produce rods with different mean diameters.

Cumulative area of test statistic is 0.5910

The test is a two-tailed test.

P-value = 2(1 - 0.5910) = 2×0.409 = 0.818

(b) Difference in mean = 8.73 - 8.68 = 0.05

pooled sd = sqrt(pooled variance) = sqrt(0.38) = 0.62

Critical value (t) = 2.042

E = t×pooled sd/√n1+n2 = 2.042×0.62/√15+17 = 0.22

Lower limit of difference in mean = 0.05 - 0.22 = -0.17

Upper limit of difference in mean = 0.05 + 0.22 = 0.27

95% confidence interval for the difference in mean rod diameter is between a lower limit of -0.17 and an upper limit of 0.27.

3 0

4 years ago

Answers for 11,12,13

lisabon 2012 [21]

My picture for 11 shows how you would set that up. S is the midpoint meaning it is directly in the center so both sides will be equal.
5x+17=8x-31
48=3x
16=x
now put that in for the x in RS
5(16)+17
80+17
RS=97

12)
same as 11 but you have a picture already. if a line bisects it then it is cut into 2 equal parts.
4-5x=2x+25
-21=7x
-3=x
put it in for both halves of AC
(4-5(-3))+(2(-3)+25)
4+15-6+25
AC=38

13)
You can find DE by subtracting CD by CE (49)
since we already have CE we just have to find CD which is equal to AC which has been set up in the same way as 11 and 12 except now we'll have to set up the equation differently.
2(3x+4)=11x-17
it's set up like this because we only have one half and the whole line.
2 times the half equals the lines length.
6x+8=11x-17
25=5x
5=x
put that in for the line AC
11(5)-17
55-17
38
and so CD equals 38
going back to the original solution:
DE=CE-CD
DE=49-38
DE=11

8 0

3 years ago