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motikmotik
3 years ago
5

Find the solution(s) of the following equation.

Mathematics
1 answer:
denpristay [2]3 years ago
8 0

Answer:

C and D

Step-by-step explanation:

a= 8 and -8

8*8=64 and -8*-8 is 64

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Michaela caught 3 fish, which weigh a total of 19 1/2 pounds. One fish weighs 7 5/8 pounds and another weighs 5 3/4 pounds. How
Serjik [45]

Answer:

ANSWER: 6 1/8

Step-by-step explanation:

Steps:

7 5/8 + 5 3/4

7 5/8 + 5 6/8

12 11/8

13 3/8

19 1/2 - 13 3/8

19 4/8 - 13 3/8

6 1/8

ANSWER: 6 1/8

6 0
3 years ago
Matthew has 3 1/4 gallons of lemonade. He sells 4/8 of the lemonade. How many gallons of lemonade does Matthew have left?
Yanka [14]

Answer:

He would have 11/4 gallons of lemonade or 2 3/4

Step-by-step explanation:

8 0
3 years ago
HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
4 years ago
PLEASE HELP ME PLEASEEEEEEEEE
dolphi86 [110]
That answer I C. I hope this helps!!!!
8 0
3 years ago
What is the seventh term of a geometric sequence that has a common ratio of –3 and the first term is –4?
rjkz [21]
An= A1 r ^(n-1)
An= -4 (-3)^(n-1)
An= -4 (-3)^(7-1)
An= -4 (729)
An= -2916

I think this is right :)
4 0
3 years ago
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