(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
To calculate area of a Square you'll take a side and square it for example
48ft of fence
48/4=12
Now you'll square
12ft^2
I hope this works...
Answer:
Bus B travel faster
Step-by-step explanation:
The graph of the question in the attached figure
we know that
the linear equation in slope intercept form is equal to
where
m is the slope
b is the y-intercept
x ---> is the time in hours
y ---> is the distance in miles
In this problem we have
Bus A
The slope of the linear equation represent the speed of the bus
so
The speed of bus A is
Bus B
Find the slope
take two points from the graph
(0,0) and (3,200)
The formula to calculate the slope between two points is equal to
substitute
Compare the slope Bus A with the slope Bus B
therefore
Bus B travel faster
L = w - 20
12000 = w × ( w - 20 )
12000 = w^2 - 20w
w^2 - 20w - 12000 = 0
( w - 10 ) ( w - 10 ) = 0
width = 10
i am a mathematics teacher. if anything to ask please pm me
