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Semmy [17]
3 years ago
11

?− 4 = –11 please answer in steps

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

<u>-7</u>-4=-11

Step-by-step explanation:

-7 - 4 = -11

If you add -11 with +4 you will get -7.

So you have -11+4=-7

         and      -7-4=-11

hope this helps

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3/5 chance of the student being a girl
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The results of a car race are shown. Determine who drove fastest. Explain. (Cutwright 35 laps, 84 min)(Evans 42 laps, 96.6 min)(
dsp73
Speeds
cutwrigth =35/84 =5/12 laps/min =0.417
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On a map, two locations are 0.75 centimeter apart. Their actual distance is 15 kilometers apart.
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6 0
4 years ago
An ectopic pregnancy is twice as likely to develop when the pregnant woman is a smoker as it iswhen she is a nonsmoker. If 32 pe
Dmitriy789 [7]

Answer:

48.48%

Step-by-step explanation:

Let's assume that there is a number N of women.

32% of these are smokers, then there are 0.32*N smokers

then 68% of these are non-smokers, then there are 0.68*N non-smokers.

Let's assume that the probability of having a ectopic pregnancy for a non-smoker is p (and the probability for a smoker will be 2*p)

Then the number of women with an ectopic pregnancy that are non-smokers is:

p*0.68*N

The number of women with an ectopic pregnancy that are smokers is:

2*p*0.32*N

Then the total number of women with an ectopic pregnancy will be:

p*0.68*N + 2*p*0.32*N

The percentage of women having an ectopic pregnancy that are smokers is equal to the quotient between the number of women with an ectopic pregnancy that are smokers and the total number of women with an ectopic pregnancy, all that times 100%.

The percentage is:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\%

Taking p and N as common factors, we get:

P = \frac{2*p*0.32*N}{p*0.68*N + 2*p*0.32*N} *100\% = \frac{N*p}{N*p} \frac{2*0.32}{0.68 + 2*0.32} *100\%

Then we get:

\frac{2*0.32}{0.68 + 2*0.32} *100\% = 48.48\%

8 0
3 years ago
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C. 69.08 inches thanks and have a great day !
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