Answer:
The distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place)
Step-by-step explanation:
Given the points
The distance 'd' between (3,4) and (4,-6)
![\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):](https://tex.z-dn.net/?f=%5Cmathrm%7BCompute%5C%3Athe%5C%3Adistance%5C%3Abetween%5C%3A%7D%5Cleft%28x_1%2C%5C%3Ay_1%5Cright%29%2C%5C%3A%5Cleft%28x_2%2C%5C%3Ay_2%5Cright%29%3A)
![d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5Cleft%28x_2-x_1%5Cright%29%5E2%2B%5Cleft%28y_2-y_1%5Cright%29%5E2%7D)
substituting the points values
![=\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%5Cleft%284-3%5Cright%29%5E2%2B%5Cleft%28-6-4%5Cright%29%5E2%7D)
![=\sqrt{1+10^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B1%2B10%5E2%7D)
![=\sqrt{1+100}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B1%2B100%7D)
![=\sqrt{101}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B101%7D)
units (Rounded to the nearest the Tenths Place)
Thus, the distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place)
Y-b/m=x (you just move everything to the other side)
Answer:
![\frac{1}{2} \times (7.5 + 2.5) \times 2.5 = 12.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%20%287.5%20%2B%202.5%29%20%5Ctimes%202.5%20%3D%2012.5)
..........................................................the answer is 12.5
So first you plug in (8,3) into their respective places, which makes it:
3= 5(8)-7
Solve
3 = 40-7
3 does not equal 33,
So the answer is no