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3 years ago

Enter the value of n so that the expression (3y+1)+(2y+8) is equivalent to (ny+9)

Mathematics

2 answers:

Mariulka [41]3 years ago

5 0

It will be equivalent to (5y+9)

hope i was able to help and i wasn’t to late.

Ganezh [65]3 years ago

5 0

Answer:ikd

Step-by-step explanation:

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If p varies directly with q, and p = 10 when q = 5, what is the value of p when q = 20

Inessa [10]

The value of p would be 40. This is because the ratio of p:q = 10:5. this could be simplify into p:q = 2:1. Applying the ratio p:20 = 2:1, P=40.

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2 years ago

Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.480

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Step-by-step explanation:

The nth term of a geometric progression can be determined by using the formula:

Tn=arn−1

where: a = first term and r = common ratio

Substitute the given values of first term and common ratio into the formula:

Tn=arn−1

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3 years ago

Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares

FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

$f(x)=\frac{24}{1+e^{-1.3x}}$

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at $y=\frac{24}{2}$ i.e between 0 to 12

So, we can take $y=\frac{24}{2}$ and then solve for x.

$\frac{24}{2}=\frac{24}{1+e^{-1.3x}}$

⇒ $2=1+3\exp{-1.3x}$

⇒ $1=3.\exp{-1.3x}$ ⇒ $\frac{1}{3}=\exp{-1.3x}$

⇒ log 3=-1.3x

⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82

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4 years ago