Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Hey! The answer is in the attachment.
Source : Done from 'My Paint'
Answer:
Area of rectangle PLUM = 75.00 square units
Step-by-step explanation:
Since diagonal of rectangle divides the rectangle into two equal triangles,
Therefore, area of the rectangle PLUM = 2× area of triangle PLM
By the mean proportional theorem,
In ΔPLM,
AP² = AM × AL
6² = AM × 8
AM =
AM = 4.5 units
Area of PLM =
=
=
= 12.5 × 3
= 37.5 units²
Now area of rectangle PLUM = 2×37.5 = 75 units²
Therefore, area of the rectangle is 75.00 square units.