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Aleonysh [2.5K]
3 years ago
5

Ginger buys lunch at school every day. She always gets pizza when it is

Mathematics
2 answers:
anyanavicka [17]3 years ago
6 0

Answer:

2/10 20%

Step-by-step explanation:

Anna007 [38]3 years ago
6 0

Answer:

B. 0.2

Step-by-step explanation:

A.p.e.x

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12 = m(-2) <br> What is m?
Svet_ta [14]

Answer:6

Step-by-step explanation:

6 0
3 years ago
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Letter C: Try doing 1 thru 6 if you don't know all of them then that's ok just tell what you know
velikii [3]

1.<

2.>

3.>

4.<

5.<

6.>

Hope this helps!

7 0
3 years ago
wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
How can you check your answer?
mars1129 [50]

Answer:

Option D is correct

Step-by-step explanation:

Multiply 7 by 3. then add 3 and make sure  the answer is 24.

7 x 3 + 3 = 21 + 3 = 24

Hope this helps!

:)

3 0
4 years ago
The vertices of Figure ABCD are A(1,1), B(2,3) C(4,3) and D(5,1). If Figure ABCD is reflected over the line y = -1, find the coo
Vlad [161]

Answer:

  • <u><em>(2, - 5)</em></u>

Explanation:

<em>The line y = -1 </em>is horizontal: parallel to the y-axis.

The point<em> B (2,3)</em> is above <em>the line y = - 1 </em>at a distance equal to the y-coordinate of B (y = 3) less - 1:

  • Δy = 3 - ( - 1) = 4

When the <em>point B (2,3) </em>is <em>reflected over the line y = -1</em>, the x-coordinate does not change.  The image will be 4 units down the line y = -1, thus the y-coordinate will be - 1 - 4 = - 5.

Hence,<em> the coordinates of the vertex B'</em> are x = 2, y = - 5: (2, - 5).

7 0
3 years ago
Read 2 more answers
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