11. An AC waveform has a peak voltage of 50 VAC. What's the
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Answer:
The large sample n = 190.44≅190
The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
<u>Step-by-step explanation</u>:
Given population proportion was estimated to be 0.3
p = 0.3
Given maximum of error E = 0.04
we know that maximum error
The 85% confidence level
now calculation , we get
√n=13.80
now squaring on both sides n = 190.44
large sample n = 190.44≅190
<u>Conclusion</u>:-
Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44