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lyudmila [28]
3 years ago
8

I need to know what the variable is and please give me the equation.

Mathematics
1 answer:
Mumz [18]3 years ago
6 0

Answer:

$9.50 = .25x

Step-by-step explanation:

38 quarters

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viktelen [127]
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What are the zero(s) of the function f(x)=4x2-36x over x-9
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4 years ago
If cos x= 5/13 and sin x &lt;0 find cos (x/2) and sin (2x)
taurus [48]
We know that

if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant

cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13

Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13

the answer Part A) is 
cos (x/2)=-6√√13/13

Part B) sin (2x)
sin (2x)=2*sin x* cos x------> 2*[-12/13]*[5/13]----> -120/169

the answer Part B) is 
sin(2x)=-120/169
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