Answer:
Mean = 1.9
Standard deviation = 0.6
Step-by-step explanation:
The Mean is calculate by the formula:
⇒
Thus Mean to the nearest tenth is 1.9
Standard Deviation is the square root of sum of square of the distance of observation from the mean.
where, is mean of the distribution.
Putting all values in the formula, We get
Standard Deviation = 0.597 ≈ 0.6
Solution :
To claim to be tested is whether "the mean salary is higher than 48,734".
i.e. μ > 48,734
Therefore the null and the alternative hypothesis are
and
Here, n = 50
s = 3600
We take , α = 0.05
The test statistics t is given by
t = 2.15
Now the ">" sign in the sign indicates that the right tailed test
Now degree of freedom, df = n - 1
= 50 - 1
= 49
Therefore, the p value = 0.02
The observed p value is less than α = 0.05, therefore we reject . Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.