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3 years ago

Does the graph represent a function? Pls help

Mathematics

1 answer:

serious [3.7K]3 years ago

5 0

Answer:

Yes

Basically a scatter plot is a type of function.

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Kevin bought 4/6 pounds of pecans for $50.89. About how much was the cost per pound?

sukhopar [10]

Answer:

$76.33

Step-by-step explanation

1 divided by 4/6 = 3/2 =1.5

50.89 x 1.5 =$76.33

5 0

3 years ago

Can somebody help me please with both of these questions??

klio [65]

Answer:

The slope is -2

Step-by-step explanation:

m =

y2 - y1

x2 - x1

that's the formula

4 0

2 years ago

Urgent help! Simplify (x − 4)(4x^2 + x − 6).

m_a_m_a [10]

Answer:

2X-1

Step-by-step explanation:

as far as i got

6 0

2 years ago

Could some please help and explain?

Sophie [7]

Answer:

x = 7

Step-by-step explanation:

A rhombus is a parallelogram where all sides are equal. Therefore, as we know two sides are equal to 7x+8 and 9x-6, we can say that

7x+8 = 9x - 6

subtract 7x from both sides to put the variable on one side

2x - 6 = 8

add 6 to both sides to isolate the variable and its coefficient

2x = 14

divide both sides by 2 to isolate x

x = 7

7 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in slope-intercept formula, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of k and m.

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago