Answer:
The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation. So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation.
Answer:
25. 
26. 
Step-by-step explanation:
For 25:
(area of a trapezoid)
(substitute terms)
(collect like terms)
(reduce the fraction by crossing out 2)
(calculate)
For 26:
(equation of area of a circle)
(enter the radius)
(communtative property to reorder the terms)
Answer:
4(5x-8) (x+5)
Step-by-step explanation:
4(5x^2+17x-40)
4(5x-8) (x+5)
Answer:
8 + 2x = 30
Step-by-step explanation:
Given,
The initial number of push-ups he does in each day = 8,
And, the number of push-ups, he increases per day = 2,
Let x be the number of days after he will reach his target of 30 push-ups,
Since, the number of push-ups she will increase in x days = 2x,
Thus, the number of push-ups she will do after x days = 8 + 2x,
⇒ 8 + 2x = 30, which is the required equation.
in short, you simply pick a few random "x" values, to get the "y", and that's your point, for example say x = 2, then y = -(2)² - 4 => y = -8, that gives us the point of (2, -8), and so on.
we can start off by finding the vertex, the U-turn of the graph, and then just pick a point to its left side and a point to its right side, and we can get the vertex of that by
![\bf y=-4x^2-4\implies y=-4x^2+0x-4 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-4}x^2\stackrel{\stackrel{b}{\downarrow }}{+0}x\stackrel{\stackrel{c}{\downarrow }}{-4} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{0}{2(-4)}~,~-4-\cfrac{0}{4(-4)} \right)\implies (0~,~-4-0)\implies (0,-4)](https://tex.z-dn.net/?f=%5Cbf%20y%3D-4x%5E2-4%5Cimplies%20y%3D-4x%5E2%2B0x-4%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bvertex%20of%20a%20vertical%20parabola%2C%20using%20coefficients%7D%20%5C%5C%5C%5C%20y%3D%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B-4%7Dx%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B0%7Dx%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B-4%7D%20%5Cqquad%20%5Cqquad%20%5Cleft%28-%5Ccfrac%7B%20b%7D%7B2%20a%7D~~~~%20%2C~~~~%20c-%5Ccfrac%7B%20b%5E2%7D%7B4%20a%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28-%5Ccfrac%7B0%7D%7B2%28-4%29%7D~%2C~-4-%5Ccfrac%7B0%7D%7B4%28-4%29%7D%20%5Cright%29%5Cimplies%20%280~%2C~-4-0%29%5Cimplies%20%280%2C-4%29)
and since it's a vertical parabola, the axis of symmetry comes from the x-coordinate of the vertex, namely x = 0, check the picture below.
