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3 years ago

Help!!! iready!!!!!!!!!

Mathematics

2 answers:

tino4ka555 [31]3 years ago

6 0

Answer:

Third or first one ✨

Step-by-step explanation:

ik I’m not much help but I’ve lost braincells

MAVERICK [17]3 years ago

5 0

Answer:

3 1/4

your welcome

the answer is c the third one

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A researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic

Delvig [45]

Answer:

90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

Step-by-step explanation:

We are given that a researcher examines 27 water samples for iron concentration. The mean iron concentration for the sample data is 0.802 cc/cubic meter with a standard deviation of 0.093.

Firstly, the pivotal quantity for 90% confidence interval for the population mean iron concentration is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean iron concentration = 0.802 cc/cubic meter

s = sample standard deviation = 0.093

n = number of water samples = 27

$\mu$ = population mean

<em>Here for constructing 90% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.706 < $t_2_6$ < 1.706) = 0.90 {As the critical value of t at 26 degree of

freedom are -1.706 & 1.706 with P = 5%}

P(-1.706 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 1.706) = 0.90

P( $-1.706 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $1.706 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X -1.706 \times {\frac{s}{\sqrt{n} }$ , $\bar X +1.706 \times {\frac{s}{\sqrt{n} }$ ]

= [ $0.802 -1.706 \times {\frac{0.093}{\sqrt{27} }$ , $0.802 +1.706 \times {\frac{0.093}{\sqrt{27} }$ ]

= [0.771 , 0.832]

Therefore, 90% confidence interval for the population mean iron concentration is [0.771 , 0.832].

4 0

3 years ago

Jarred wants to by a go-cart for $1,200

dybincka [34]

the go cart costs 1200

6 0

3 years ago

SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

$C=180-(A+B)$

$C=180-(21.24+27.14)$

$C=131.62$

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

$b^2=a^2+c^2$

$4^2=2^2+c^2$

$16=4+c^2$

$12=c^2$

$c=\sqrt{12}$

$c=2\sqrt{3}$

- We can find angle C using the cosine trig identity

$cos(C)=\frac{adjacent}{hypotenuse}$

$cos(C)=\frac{2}{4}$

$C=arccos(\frac{2}{4} )$

$C=60$

- Now we can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+60)$

$A=30$

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+34.88)$

$A=55.12$

- We can find side a using the tangent trig identity

$tan(C)=\frac{opposite-side}{adjacent-side}$

$tan(34.88)=\frac{7}{a}$

$a=\frac{7}{tan(34.88)}$

$a=10.04$

- Now we can find side b using the Pythagorean theorem

$b^2=a^2+c^2$

$b^2=10.04^2+7^2$

$b^2=149.8$

$b=\sqrt{149.8}$

5 0

3 years ago

Which is the graph of the function f(x)= negative square root x

Vsevolod [243]

First, note that $\sqrt{x}$ is always positive (except for x=0), so $-\sqrt{x}$ must be always negative.

Thus, the only plausible graphs are 1 and 3 since they are below the x-axis.

Now, $\sqrt{x}$ and $-\sqrt{x}$ are only defined for x≥0, because only for these x'es we can take the square root.

Note that the third graph has domain (-infinity, 0], so it is not the right one, while 1 is ok.

Answer: first graph

6 0

3 years ago

What is this this sos 3x-y=3? (x,y)=?

Mazyrski [523]

Rewrite the equation;

3x-y=3
3x-3=y

Linear equation.

I'm unsure of what the second part asks. Can you rewrite the given question?

6 0

3 years ago