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makkiz [27]
3 years ago
10

How do you simplify this expression then evaluate it if x=2? 5x - 2 + 3 - x

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0

You just put all of the like terms together, if it has an X combine it and if it doesn't have an X combine it. You end up with 4x-5

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Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
Given that R = 4 x + 8 y Find y when x = 4 and R = 32
victus00 [196]

R = 4 x + 8y [ Given ]

when ,

x = 4 and R = 32

★ Substituting the values

=> 32 = 4 × 4 + 8y

=> 32 = 16 + 8y

=> 8y = 32 - 16

=> 8y = 16

=> y = 8/16

=> y = 2

7 0
3 years ago
Read 2 more answers
The point slope form of the equation of the line that passes through (-5,-1) and (10,-7) is y+7= -2/5(x-10) what is the standard
Alex787 [66]
Standard form for y+7=-2/5(x-10) is y=-7-2/5(x-10)
3 0
3 years ago
Plss help i’ll give brainliest thank you!
Art [367]

Answer:

its 45 as3*15 is 45 and 45*1 is 45

plz mark me branliest

5 0
3 years ago
Read 2 more answers
Help me asap please
lapo4ka [179]

6^4

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8 0
3 years ago
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