Question

What's the pattern for 2,4,7,9

Answer 1

Answer:

The pattern is this: I create a function p(x) such that

p(1)=1

p(2)=1

p(3)=3

p(4)=4

p(5)=6

p(6)=7

p(7)=9

Therefore, trivially evaluating at x=8 gives:

p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)

Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.

Step-by-step explanation: