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Mathematics

1 answer:

spin [16.1K]3 years ago

4 0

Answer: Non-Linear Function line

Step-by-step explanation:

The reason is if it was a linear one then it would be a straight line and since this is not a straight line then it is a Non-Linear Function because you can't just look at it and see what the increase and decrease was for a certain time period.

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X² - 5x + 6 = 0 (R: 2, 3)

Firlakuza [10]

I'm sending you two screenshots of the explanation I hope this helps.

4 0

3 years ago

if trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A’lie

maria [59]

Answer:

Answer: (second option) (-4,1)

Step-by-step explanation:

Transformations of Points and Shapes

The image shows a trapezoid ABCD where point A has coordinates (-4,1).

The following transformations are performed:

Reflection over the y-axis: If a point (x,y) is reflected over the y-axis, it becomes (-x,y). Thus point A becomes A'=(4,1)

Reflection over the x-axis: If a point (x,y) is reflected over the x-axis, it becomes (x,-y). Thus point A' becomes A''=(4,-1)

Rotation 180°: If a point (x,y) is rotated 180°, it becomes (-x,-y). Thus point A'' becomes A'''=(-4,1)

Answer: (second option) (-4,1)

5 0

3 years ago

What is CD? 6 units 12 units 18 units 24 units

tangare [24]

Answer: 18 units

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given that an intercepted arc has length 6pi inches and a central angle is pi/3, find the radius

MA_775_DIABLO [31]

$\bf \textit{arc's length}\\\\
s=r\theta \quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=6\pi \\
\theta =\frac{\pi }{3}
\end{cases}\implies 6\pi =r\left( \frac{\pi }{3} \right)\implies \cfrac{6\pi }{\frac{\pi }{3}}=r
\\\\\\
\cfrac{6\pi }{1}\cdot \cfrac{3}{\pi }=r\implies 18=r$

5 0

3 years ago

the length of a rectangle is 2 cm less than five times the width. the area of the rectangle is 16 cm^2. find the length and widt

ahrayia [7]

length = L
width = w

L = (5w-2) cm

$w(5w-2)=16 \\ 5w^2-2w-16=0 \\ D=b^2-4ac=(-2)^2-4*5*(-16)=324 \\ w_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ w_1= \frac{2- \sqrt{324} }{2*5}= \frac{2-18}{10}=-1.6 \ \ \O \\ w_2= \frac{2+18}{10}=2 cm$

width = 2 cm
length = 5w-2 = 5*2-2 = 8 cm

8 0

3 years ago