Answer:
Step-by-step explanation:
Yes, the irrational number stays irrational.
Make the assumption that this statement is false and that a rational and an irrational can produce a rational. x is irrational. Assume that a, b, c, and d are all integers. If you like, they can be relatively prime to each other.
a/b + x = c/d Subtract a/b from both sides.
x = c/d - a/b Now put the 2 fractions over a common denominator.
x = (c*b - d*a)/(b*d) Investigate what you have.
b*d are two integers multiplied together. multiplication of integers is closed (the answer will be an integer).
cb and da are also integers. subtracted integers are also closed under subtraction.
But
Here's the kicker. An irrational number is one that cannot be expressed as a fraction. Sqrt(2) for example cannot be shown to be rational. There is no fraction that equals sqrt(2)
So our proof is "bogus." It cannot work. An irrational number excludes the possibility of being able to be represented by a fraction by definition.
<span>
<u><em>The correct answers are: </em></u>1) f(x)=1/2x;
2) f(x)=2x+1;
3) f(x)=x^3;
4) f(x)=6x.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>Let x be the input. In function notation, the output is denoted by f(x).
For #1, since the output is half of the input, we want to take half of x; this would give us
f (x)=</span></span>
<span><span>x.
For #2, twice the input is 2x; one more than this is 2x+1, which gives us
f (x)=2x+1.
For #3, the cube of the input is x</span></span>³<span><span>, which gives us
f (x)=x</span></span>³<span><span>.
For #4, six times the input is 6x, which gives us
f (x)=6x.</span></span>
Answer:
i actually hope this helped :))
Answer:
The answer would be 35066 :)
Step-by-step explanation:
(y+5554) + y = 64578
Combine like terms
2y = 64578-5554
2y = 59024
y = 29512
x = 29512 + 5554 = 35066