Answer:
b) 6
Explanation:
Given
v(t)=3t²+6t
X(0) = 2
X(1) = ?
Knowing that
v(t)=3t²+6t = dX/dt
⇒ ∫dX = ∫(3t²+6t)dt
⇒ X - X₀ = t³ + 3t²
⇒ X(t) = X₀ + t³ + 3t²
If X(0) = 2
⇒ X(0) = X₀ + (0)³ + 3(0)² = 2
⇒ X₀ = 2
then we have
X(t) = t³ + 3t² + 2
when
t = 1
X(1) = (1)³ + 3(1)² + 2
X(1) = 6
Answer:
9m/s²
Explanation:
Given parameters:
Initial velocity = 30m/s
Final velocity = 0m/s
Distance traveled = 50m
Unknown:
Deceleration = ?
Solution:
To solve this problem, we apply the proper motion equation;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance
Insert the parameters and solve;
0² = 30² + 2(a)50
-900 = 100a
a = -9m/s²
The negative value indicates deceleration.
The motorcycle decelerates at a rate of 9m/s²
Conservation of energy explains that energy can only be transferred between different forms of energy
Answer: yeah it is reflection
Answer:
0.52rad/s^2
Explanation:
To find the angular acceleration you use the following formula:
(1)
w: final angular velocity
wo: initial angular velocity
θ: revolutions
α: angular acceleration
you replace the values of the parameters in (1) and calculate α:
you use that θ=22 rev = 22(2π) = 44π
hence, the angular acceñeration is 0.52rad/s^2
