Answer:
The magnitude of the new electric field is <u>35820 N/C</u>.
Explanation:
Given:
Original magnitude of electric field (E₀) = 2388 N/C
Original voltage = 'V' (Assume)
Original separation between the plates = 'd' (Assume)
Now, new voltage is three times original voltage. So, 
New distance is 1/5 the original distance. So, 
Now, electric field between the parallel plates originally is given as:
Let us find the new electric field based on the above formula.
Now, 
. So,
Therefore, the magnitude of the new electric field is 35820 N/C.
Answer:
(a) 8.117 (b) 0.742
Explanation:
We have given distance s =40 m time t=7.5 sec
Final velocity v =2.55 m/sec
From the first equation of motion 
(negative sign because there is retrdation as the truck speed is slowing down )
So 
--------------eqn 1
From the second equation of motion 
( negative sign because there is retrdation as the truck speed is slowing down )
So 
------------------eqn 2
On solving eqn1 and eqn 2
u=8.117 m/sec and a=-0.742
Potential energy is energy stored in an object due to its position or arrangement. Kinetic energy is energy of an object due to its movement - its motion. ... Potential energy can be converted into kinetic energy, and kinetic energy can be converted into potential energy
C I completed the same quiz
Answer:
v=0.60 m/s
Explanation:
Given that
m ₁= 390 kg ,u ₁= 0.5 m/s
m₂ = 250 kg ,u₂ = 0.76 m/s
As we know that if there is no any external force on the system the total linear momentum of the system will be conserve.
Pi = Pf
m ₁u ₁+m₂u₂ = (m₂ + m ₁ ) v
Now putting the values in the above equation
390 x 0.5 + 250 x 0.76 = (390 + 250 ) v
v=0.60 m/s
Therefore the velocity of the system will be 0.6 m/s.
