Look at the fractions!
9/10 is less than 1.
10/9 is more than 1. So it must be more than 9/10.
Answer:
#1 c. -1
#2 b. 1 is less than or equal to x which is less than or equal to three
#3 a. 37.5 is less than or equal to y which is less than or equal to 87.5
#4 b. 3
#5 b. (2, 3, 4, 5, 6)
#6 d. (45, 55, 65, 75, 85)
Step-by-step explanation:
Domain is the x value and y is the range. For #1 the answer is c because you can't go golfing for -1 hours. For #2, the answer is b because they are all the acceptable values for the domain which is represented by x and x is the time spent at the golfing bay. The answer would not be c because you could go to the bay for 2.75 hours it doesn't have to be just 1, 2, 3. For #3 the concept is similar because the range aka total cost can be all the values in between 37.5 and 87.5. For #4 a reasonable domain value which is number of people is 3 because you can't have 2.5 people and you can't have -4 people and thus all of the above isn't possible leaving three. #5 is b because you can only have those set numbers to represent people. If you chose a that would mean you could have 1.5 people which isn't possible thus only numbers 2, 3, 4, 5, and 6 are possible. For #6 The answer is d because when you plug in numbers 2, 3, 4, 5, 6 into the x value one at a time and solve the equation, those numbers equal t. Just use your basic knowledge to figure these out there isn't much math you just have to know that domain means x and range means y. y is 9/10 always by itself on one side of the equal sign. When in doubt think, can I have a half a person. Think of the real world and apply to math. Goof luck on future problems!
Answer:
x=amount invested at 7%
2x=amount invested at 8%
3x=amount invested at 9%
interest=principal*rate*time (time=1 year)
$150=0.07x+0.08*2x+0.09*3x
$150=0.07x+0.16x+0.27x
$150=0.50x
$1500=5x
x=$300 invested at 7%
2x=$600 invested at 8%
3x=$900 invested at 9%
Step-by-step explanation:
for this question you would need to utilize ratios to find the side lengths. For example, set up a ratio between the big triangle with the small triangle to find a side length
