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elena55 [62]
3 years ago
10

Could you show me how to divide x^3 + 2x^2 + x + 2 by x^2 + 1

Mathematics
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

x+2

Step-by-step explanation:

For this division we can first use factoring of the numerator, then eliminate the common factors.

\frac{x^{3} +2x^{2} +x+2}{x^{2}+1 }

Factoring the numerator by the term grouping method

\frac{x^{2} (x+2)+(x+2) }{x^{2} +1}

\frac{(x^{2} +1)(x+2)}{x^{2} +1}

removed terms

(x+2)

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Pls pls help me !!!!
Rudik [331]
3,-2 is the right answer i think
7 0
3 years ago
Find the percent of markup. 37.00 to 49.00
Wewaii [24]
So, 100 * (49-37) / 37..You always do whats in parenthesis first; 49-37=12. Then you do multiplication and division, since multiplication comes first we do; 100*12=1200/37. Rounding to the nearest tenth would be 32%
6 0
3 years ago
Read 2 more answers
i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.
Natali [406]

Answer:

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = 7

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = -5\sqrt 2

Step-by-step explanation:

Given

N = (-7,-1) --- terminal side of \varnothing

Required

Determine the values of trigonometric functions of \varnothing.

For \varnothing, the trigonometry ratios are:

sin\ \varnothing = \frac{y}{r}       cos\ \varnothing = \frac{x}{r}       tan\ \varnothing = \frac{y}{x}

cot\ \varnothing = \frac{x}{y}       sec\ \varnothing = \frac{r}{x}       csc\ \varnothing = \frac{r}{y}

Where:

r^2 = x^2 + y^2

r = \sqrt{x^2 + y^2

In N = (-7,-1)

x = -7 and y = -1

So:

r = \sqrt{(-7)^2 + (-1)^2

r = \sqrt{50

r = \sqrt{25 * 2

r = \sqrt{25} * \sqrt 2

r = 5 * \sqrt 2

r = 5 \sqrt 2

<u>Solving the trigonometry functions</u>

sin\ \varnothing = \frac{y}{r}

sin\ \varnothing = \frac{-1}{5\sqrt 2}

Rationalize:

sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

sin\ \varnothing = \frac{-\sqrt 2}{5*2}

sin\ \varnothing = \frac{-\sqrt 2}{10}

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{x}{r}

cos\ \varnothing = \frac{-7}{5\sqrt 2}

Rationalize

cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}

cos\ \varnothing = \frac{-7\sqrt 2}{10}

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{y}{x}

tan\ \varnothing = \frac{-1}{-7}

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = \frac{x}{y}

cot\ \varnothing = \frac{-7}{-1}

cot\ \varnothing = 7

sec\ \varnothing = \frac{r}{x}

sec\ \varnothing = \frac{5\sqrt 2}{-7}

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = \frac{r}{y}

csc\ \varnothing = \frac{5\sqrt 2}{-1}

csc\ \varnothing = -5\sqrt 2

3 0
3 years ago
Solve for x. Evaluate and round your answer to 1 decimal place(tenths place). 10x=1200
Mandarinka [93]

Answer:

<h2>x = 3.1</h2>

Step-by-step explanation:

<h3>{10}^{x}  = 1200</h3>

<u>To solve first take logarithm to both sides</u>

That's

<h3>log_{10}(10) ^{x}  =  log_{10}(1200)</h3><h3 /><h3>log_{10}(10)^{x}  = x log_{10}(10)</h3>

But

<h3>log_{10}(10)  = 1</h3>

So we have

x =  log_{10}(1200)

<u>Write 1200 as a number with the factor 100</u>

That's

1200 = 100 × 12

So we have

<h3>x =  log_{10}(100 \times 12)</h3>

<u>Using the rules of logarithms</u>

That's

<h3>log_{a}(x \times y)  =  log_{a}(x)  +  log_{a}(y)</h3>

Rewrite the expression

That's

<h3>x =  log_{10}(100)  +  log_{10}(12)</h3><h3 /><h3>x =  log_{10}(10)^{2}  +  log_{10}(12)</h3><h3>x = 2 log_{10}(10)  +  log_{10}(12)</h3><h3>log_{10}(10)  = 1</h3><h3 /><h3>x = 2 +  log_{10}(12)</h3>

x = 3.079

So we have the final answer as

<h3>x = 3.1 to one decimal place</h3>

Hope this helps you

8 0
3 years ago
Find the Area.<br>help sos I need it please I have 15 minutes left to complete this​
marysya [2.9K]

Answer:

95

Step-by-step explanation:

6 x 10 = 60

7 x 10 / 2 = 35

35  + 60 = 95

3 0
3 years ago
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