<span>The process that a wireless router uses to translate a private ip address on internal traffic to a routable address for the internet is </span>Network address translation<span> (NAT). It is a method of relabeling one </span>IP address<span> space into another by altering network </span>address<span> information in IP header of packets while they are in transit across a </span>traffic routing<span> device. </span>
<u>Answer:</u>
<em>A prototype for a function called isPrime that returns is true.</em>
<u>Explanation:</u>
Function prototype is just a skeletal part of the function which has <em>a return type, function name and the respective parameters. </em>
There is a difference between function and function prototype.
Function is nothing but a <em>function definition</em>, where it actually has all the lines of codes which need to be processed when it is called. It can be invoked any number of times and anywhere within the<em> scope of the function</em>. <em> </em>
As per the given question, the prototype can be,
<em>bool isPrime (int);
</em>
Answer:
Pay attention in your class.
Explanation:
If you paid attention in your class, you would have at least a basic understanding of the material.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
