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Stells [14]
3 years ago
7

Read the scenario and then answer the question using only the information provided.

Computers and Technology
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

It’s b the report is sorted only

Explanation:

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Create a program that prints out a list of all the divisors of a number stored in a variable. (If you don’t know what a divisor
UkoKoshka [18]

Answer:

// Program is written in C++ Programming Language

// Comments are used for explanatory purpose

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare integer variable n which serves as the quotient.

int n;

// Prompt to enter any number

cout<<"Enter any integer number: ";

cin>>n;

// Check for divisors using the iteration below

for(int I = 1; I<= n; I++)

{

// Check if current digit is a valid divisor

if(n%I == 0)

{

// Print all divisors

cout<<I<<" ";

}

}

return 0;

}

7 0
4 years ago
// This pseudocode segment is intended to compute and display
Finger [1]

The pseudocode to calculate the average of the test scores until the user enters a negative input serves as a prototype of the actual program

<h3>The errors in the pseudocode</h3>

The errors in the pseudocode include:

  • Inclusion of unusable segments
  • Incorrect variables
  • Incorrect loops

<h3>The correct pseudocode</h3>

The correct pseudocode where all errors are corrected and the unusable segments are removed is as follows:

start

Declarations

     num test1

     num test2

     num test3

     num average

output "Enter score for test 1 or a negative number to quit"

input test1

while test1 >= 0

     output "Enter score for test 2"

     input test2

     output "Enter score for test 3"

     input test3

     average = (test1 + test2 + test3) / 3

     output "Average is ", average

     output "Enter score for test 1 or a negative number to quit"

     input test1

endwhile

output "End of program"

stop

Read more about pseudocodes at:

brainly.com/question/11623795

3 0
2 years ago
There is a simple method for constructing a magic square for any odd value of n:
DaniilM [7]

Answer:

See Explaination

Explanation:

class MagicSquare():

def __init__(self,side):

self.side=side

self.two_dimension=[]

for row in range(1,side+1):

row_line=[]

for col in range(1,side+1):

row_line.append(0)

self.two_dimension.append(row_line)

def display(self):

row=0

col=int((self.side-1)/2)

for i in range(1,self.side**2+1):

self.two_dimension[row][col]=i

row-=1

col+=1

if row==-1:

row=self.side-1

if col==self.side:

col=0

if self.two_dimension[row][col]==0:

continue

else:

row+=1

if row==self.side:

row==0

for line in self.two_dimension:

for num in line:

print("{0:>3}".format(num),end=" ")

print()

def main():

for i in range(1,14,2):

square=MagicSquare(i)

square.display()

print("----------------------------------------------------")

if __name__ == '__main__':

main()

3 0
4 years ago
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