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3 years ago

Question 11

Mathematics

2 answers:

Alex3 years ago

5 0

Answer:

C. 9

Step-by-step explanation:

Plug in 5 for x in which you should get the equation 4(5)-11. Multiply the first two numbers to get 20 and subtract 11 to get your final answer which is 9.

Temka [501]3 years ago

4 0

Answer:

C)9

Step-by-step explanation:

turn in 5 for x which will leads to 4(5)-11, then multiply the first two number since there are parentheses. After multiplying you should get 20, after that step you have to subtract 11 from 20. 20-11=9 so therefore 9 is your answer

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.33333 as a fraction

Varvara68 [4.7K]

Answer:

1/3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Suppose that IQ scores have a bell-shaped distribution with a mean of

Svetllana [295]

Answer:

68 %

Step-by-step explanation:

The Empirical rule formula states that:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 96 and a Standard deviation of 17

Applying , the first empirical rule for 1 standard deviation from the mean, we have:

μ - σ

96 - 17

= 79

μ + σ

96 + 17

= 113

Therefore, the percentage of IQ scores that are between 79 and 113 is 68%

6 0

3 years ago

Graph the line represented by the equation.

harina [27]

Answer:

Step-by-step explanation:

first you need to put the equation in y=mx+b form

y-3=(-1/2)(x+4)

y-3= (-1/2x)+4

y=-1/2x+1

then you just graph

the y intercept is 1 and the slope is -1/2 so it’s going to be a negative graph and it starts from 1 on the y axis

5 0

3 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

I need help with my science work

melomori [17]

Q3) Ba= 2
N= 6
O = 18

7 0

3 years ago