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bulgar [2K]
3 years ago
11

Sara has 6 chapters to read over 4 days. How many chapters will she need to read each day?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Answer:

1 and a half per day.

Step-by-step explanation:

6/4 = 1.5

Day 1: Chapters 1 and half of 2

Day 2: Chapters half of 2 and 3

Day 3: Chapters 4 and half of 5

Day 4: Chapters half of 5 and 5

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3 years ago
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Find symmetric equations for the line of intersection of the planes. z = 4x − y − 13, z = 6x + 5y − 13
MArishka [77]
The intersection line of two planes is the cross product of the normal vectors of the two planes.

p1: z=4x-y-13 => 4x-y-z=13
p2: z=6x+5y-13 => 6x+5y-z=13
The corresponding normal vectors are:
n1=<4,-1,-1>
n2=<6,5,-1>

The direction vector of the intersection line is the cross product of the two normals, 
vl=
 i   j   k
4 -1 -1
6  5 -1
=<1+5, -6+4, 20+6>
=<6,-2,26>
We simplify the vector by reducing its length by half, i.e.
vl=<3,-1,13>

To find the equation of the line, we need to find a point on the intersection line.
Equate z:  4x-y-13=6x+5y-13 => 2x+6y=0 => x+3y=0.
If x=0, then y=0, z=-13 => line passes through (0,0,-13)

Proceed to find the equation of the line:
L: (0,0,-13)+t(3,-1,13)
Convert to symmetric form:
\frac{x-0}{3}=\frac{y-0}{-1}=\frac{z-(-13)}{13}
=>
\frac{x}{3}=\frac{-y}{1}=\frac{z+13}{13}

3 0
3 years ago
Simplify problem: ∛-27n^27
enot [183]

Answer:

-3n⁹

Step-by-step explanation:

= \sqrt[3]{-27n^(27)}

= \sqrt[3]{-27} * \sqrt[3]{n^{27}}

= (-3) × n⁹

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5 0
3 years ago
Find an equation of the line is the perpendicular to 30X-5Y=5 and passes through the point (0,-3).
timurjin [86]

Answer:

y = (\frac{-1}{6})x - 3

Step-by-step explanation:

Given line = 30x - 5y = 5 or y = 6x + 1

so, the slope of the given line is 6.

now, let the line which is perpendicular to the given line be y = mx + c

where,

m = slope of the line

c = constant

As we know, if two lines are perpendicular to each other, the value of product of there slopes are -1.

so, slope of given line × slope of perpendicular line = -1

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⇒ m = \frac{-1}{6}

By substitutiong the value of m in the equation, we get;

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For c,

as the point (0,-3) passes through the line, we get;

⇒ -3 = (\frac{-1}{6})(0) + c

⇒ c = -3

Hence,

The line which is perpendicular to the given line and passes through (0,-3) is  y = (\frac{-1}{6})x - 3 .

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