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Brums [2.3K]
3 years ago
12

4x^2+bx+9=0 has no real number solutions what must be true about b​

Mathematics
1 answer:
timama [110]3 years ago
4 0

b^2-4ac<0 b^2-144<0 (b-12)(b+12)<0

-12<b<12

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Pentagon G was dilated from the origin by a scale factor of one half to create Pentagon G′. Which statement explains why the pen
Sergio [31]

Answer:

the answer is Dilations preserve betweenness of points; therefore, the corresponding sides of pentagons G and G′ are proportional.

Step-by-step explanation:

i took the test and got it right

8 0
2 years ago
Please help <br><br> Thank you
san4es73 [151]

Answer:

m ∠JPN = 131°    

Step-by-step explanation:

m ∠JPL = m ∠MPK                         Vertical angles are =

7x + 19 = 11x -17                               Substitution  

- 4x =  -36                                      Algebra: Solving for x

   x = 9                                           Algebra: Solving for x

 m ∠JPL = 82°                              Substitution x = 9 into m ∠JPL = 7x +19

m ∠JPL + m ∠LPK = 180°             Definition of linear pair/supplement

                                                     angles = 180°

82° + m ∠LPK = 180°                      Substitution    

            m ∠LPK = 98°                     Algebra

m ∠LPK = m ∠LPN + m ∠NPK        Angle addition Theorem

       PN bisects ∠LPK                     Given    

m ∠LPN = m ∠NPK                          Definition of angle bisector

98 ° = 2 ( m ∠LPN)                           Substitution  

    m ∠LPN = 49°                             Algebra

m ∠JPN = m ∠JPL + m ∠LPN         Angle Addition

 m ∠JPN = 82° + 49°                     Substitution  

m ∠JPN = 131°                                 Addition    

7 0
2 years ago
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emmasim [6.3K]

Answer:

1\4

Step-by-step explanation:

i did it out of 100 i choose 25/100

then id you simplified that 25 goes into 100 4 times 25 goes into int self one time so the answer is 1/4

4 0
2 years ago
A line segment has endpointsA(-5, 1) and b(-3, 3) what is the midpoint of the segment​
Galina-37 [17]
The mid point of the segment would be (-4,2)
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