The answer is A:
Because the only difference between the rest of the answer choices are the lower and upper quartiles, that is all you need to find. In order to do so you find the median for the first half (lower quartile) and then find the median for the second half. In this case it is 29 (Q1) and 58 (Q2)
Answer:
516
Step-by-step explanation:
Step 1:
258 × 2 = 516
Answer:
516
Hope This Helps :)
Answer:

--- Variance
Step-by-step explanation:
Given

Solving (a): Calculate the mean.
The given data is a grouped data. So, first we calculate the class midpoint (x)
For 51 - 58.

For 59 - 66

For 67 - 74

For 75 - 82

For 83 - 90

So, the table becomes:

The mean is then calculated as:



-- approximated
Solving (b): The sample variance:
This is calculated as:

So, we have:


-- approximated