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REY [17]
3 years ago
6

Which is equivalent to the expression below?

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

3√3 + √6 is the answer. so none is correct.

Step-by-step explanation:

= 3√3 + √6 + √12 - 2√3

= 3√3 + √6 + √4 X 3 - 2√3

= 3√3 + √6 + 2√3 - 2√3

= 3√3 + √6

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When trying to solve a system of equations graphically, our focus is on identifying the coordinates of any point through which the graphs go. Look at the above graph: you'll see that the red and the blue graphs intersect at (0,2), and so (0,2) is a "solution" of that system of equations.

Here, we're asked to answer a different kind of question: "Is (2,0) a solution to the given system of equations?" Let's paraphrase that question: "Do both graphs go through (2,0)?" The answer: emphatically not. Neither graph goes through (2,0). Thus, (2,0) is not a solution to this system of equations.


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3 years ago
Write a parallel and perpendicular equation that passes through the point (6,-2)?
Reptile [31]

Answer:

y=x-8 and y=-x+4

Step-by-step explanation:

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3 years ago
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8 0
3 years ago
Read 2 more answers
What is the cost per pound? $5.48 for 4 pounds of grapes.
Agata [3.3K]

Answer:

$1.37/lb

Step-by-step explanation:

5.48/4

4 0
3 years ago
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A $8,000 principal is invested in two accounts, one earning 1% interest and another earning 6% interest. If the total interest f
lana [24]

The amount invested in the first account is $1,500 and $6,500 was invested in the second account.

What is simple interest?

Simple interest is determined as the principal multiplied by the interest rate ,then multiplied by the duration of the investment.

The formula for simple interest on an investment is as shown below:

I=PRT

P=principal=$8,000

R=interest rates= 1% and 6%

T=duration of investment=1 year

Let assume that X was invested at 1% and that the remaining of $8000-X is invested at 6%.

Interest on the first account=X*1%*1

Interest on the first account=0.01X

Interest on second account=($8000-X)*6%*1

Interest on second account=480-0.06X

Total interest=0.01X+480-0.06X

Total interest=480-0.05X

Total interest=$405

405=480-0.05X

0.05X=480-405

0.05X=75

X=75/0.05

X=amount invested in the first account=$1,500

Amount invested in the second account=$8000-X

Amount invested in the second account=$8,000-$1,500

Amount invested in the second account=$6,500

Find out more about simple interest on:brainly.com/question/1115815

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4 0
2 years ago
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