144+256=400 are the lengths is the sides and hypotenuse
Use SOH CAH TOA and the measures of the angles are 29.36 and 60.53
Complete Question
A person standing 213 feet from the base of a church observed the angle of elevation to the church's steeple to be 33 ∘. Find the height of the church
Answer:
138.3 ft
Step-by-step explanation:
We solve this question above using using the Trigonometric function of Tangent.
tan θ = Opposite/Adjacent
Where:
Opposite = Height of the church = x
Adjacent = Distance for the base of the church = 213ft
Angle of elevation θ = 33°
Hence:
tan 33 = x /213 ft
Cross Multiply
x = tan 33 × 213 ft
x = 138.32381735 ft
x = Opposite Approximately = 138.3 ft
Therefore, the height of the church = 138.3 ft
This is in the form of a slope formula where y=mx+b. B pretty much gives you the vertical shift. Meaning that y=2/x-3 would be correct.
Answer:
2/6
Step-by-step explanation:
There are 6 numbers on a regular die, and only 2 numbers that are greater than four that you could get, so the probability of getting a number greater then 4 would be 2/6
Answer:
55.563
Step-by-step explanation:
Given the following :
Mean(m) point = 73
Standard deviation( sd) = 10.6
Lower 5% will not get a passing grade (those below the 5% percentile)
For a normal distribution:
The z-score is given by:
z = (X - mean) / standard deviation
5% of the class = 5/100 = 0.05
From the z - table : 0.05 falls into - 1.645 which is equal to the z - score
Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class
z = (x - m) / sd
-1.645 = (x - 73) / 10.6
-1 645 * 10.6 = x - 73
-17.437 = x - 73
-17.437 + 73 = x
55.563 = x
Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563
