Answer:
k = - 2
Step-by-step explanation:
Lines g(x) and f(x) passes through the points (2, 0), (0, 2) & (4, 0), (0, 4)
Since both the lines are parallel, so slopes of lines g(x) and f(x) would be same.
Therefore,
Slope of line g = Slope of line f = (2-0)/(0 - 2) = 2/-2 = - 1
Equation of line g(x)
For point (0, 2)
y- intercept (b) = 2
y = mx + b
g(x) = - 1x + 2 [y = g(x)]
g(x) = - x + 2
Equation of line f(x)
For point (0, 4)
y- intercept (b) = 4
y = mx + b
f(x) = - 1x + 4 [y = g(x)]
f(x) = - x + 4
It is given that:
g(x) = f(x) + k
g(x) - f(x) = k
(-x + 2) - (-x + 4) = k
-x + 2 + x - 4 = k
2 - 4 = k
-2 = k
k = - 2
1. 36 = 6·6 and 42 = 6·7 have a common factor of 6.
... x⁴ and x² have a common factor of x²
The GCF is 6x².
The factorization is 36x⁴ -42x² = 6x²(6x² -7)
2. All coefficients are multiples of 4. All variable factors are multiples of x³.
The GCF is 4x³.
The factorization is 4x⁵ -8x⁴ -4x³ = 4x³(x² -2x -1)
3. The GCF of coefficients 6 and 15 is (15 mod 6) = 3, which is also a factor of the other coefficients. The lowest power of m, which is m² is also a factor of the other terms.
The GCF is 3m².
The factorization is 6m⁵ -15m⁴ -21m³ +27m² = 3m²(2m³ -5m² -7m +9)
Answer:
x=-2,y=-4
Step-by-step explanation:
By dividing to lowest terms
5x – 5y = 10= x-y=2.......(1)
6x – 4y = 4=3x-2y=2........(2)
By elimination method
Multiply equation (1) by 3 so as to correspond with equation (2)
3(x-y)=3(2)
3x-3y=6..........(3)
Multiply equation (2) by 1 so as to correspond with equation (1)
1(3x-2y)=1(2)
3x-2y=2..........(4)
Then equation (3)-equation (4)
(3x-3y=6)
-
(3x-2y=2)
__________
-y=4
y=-4
Substitute y=-4 into equation(1)
x-(-4)=2
x+4=2
x=-2
Therefore x=-2,y=-4
The absolute value of x: |x|.
|x| = x if x ≥ 0 <em>examples: |5| = 5; |0| = 0; |8.34| = 8.34; |1/2| = 1/2</em>
|x| = -x if x < 0 <em>examples: |-5| = -(-5) = 5; |-8| = -(-8) = 8; |-1.2| = 1.2;</em>
<em> |-3/7| = 3/7</em>
<em>Therefore</em>
<em>
</em>
