The answer is IT STARTED THE CIVIL SERVICE COMMISSION.
The area that the car's tires occupy as they contact the road is 0.079m².
<h3>Area:</h3>
Using this formula
Area=Force/Pressure
Where:
Force=15000
Pressure=190 kpa
Let plug in the formula
Area= 15000 / 190000
Area = 0.0789 m²
Area=0.079m² (Approximately)
Inconclusion the area that the car's tires occupy as they contact the road is 0.079m².
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Answer: dendritic drainage pattern
Explanation: Fractures are mechanical breaks in rocks involving discontinuities in displacement across surfaces or narrow zones. Fracture is a term used for all types of generic discontinuities. This usage is common among scientists inside and outside the earth sciences and is used in other chapters of this report. However, different kinds of fractures exist, with different geometries, mechanical effects, and flow properties. Based on the nature of the displacement discontinuity, commonly encountered fractures can be classified into three geologically based major groups: (1) dilating fractures/joints, (2) shearing fractures/faults, and (3) closing fractures/pressure solution surfaces. Drainage pattern is the pattern formed by the streams, rivers, and lakes in a particular drainage basin. They are governed by the topography of the land, whether a particular region is dominated by hard or soft rocks, and the gradient of the land.
Answer:
Option (A)
Explanation:
The Ultraviolet lights are referred to as electromagnetic radiation that is comprised of wavelength ranging from 10 nm to about 400 nm (nanometer). The wavelengths of these UV rays are comparatively shorter in comparison to the wavelength of the visible light.
On the other hand, the infrared lights are the radiations that are comprised of wavelength ranging from about 700 nm to 1 mm (millimeter). These infrared lights have a higher wavelength in comparison to the visible light.
Those lights that are comprised of wavelength higher and shorter than the visible light wavelength are not visible to the naked eye. Human eyes respond to the light only between red and violet light of the electromagnetic spectrum.
Thus, the correct answer is option (A).
