Answer:68.27%
Step-by-step explanation:
TI84
2nd distr
normalcdf(89,97,93,4)
Answer:
a: 0.9544 9 within 8 units)
b: 0.9940
Step-by-step explanation:
We have µ = 300 and σ = 40. The sample size, n = 100.
For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:
P(292 < x < 308).
We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.
We have P(292 < x < 308) = 0.9544
Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311. We want to find
P(289 < x < 311)
We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.
We have P(289 < x < 311) = 0.9940
I'll assume the . Is meant to be a ,
One million, seventy thousand, and seventy.
Answer:

Step-by-step explanation:

Let's substitute the first equation into the second one.

- Multiply by
and bring all the terms to one side.
I'll use my graphical calculator to solve this but you could factor:
(All rounded to 2 decimal places)
Now we can substitute these
values into an equation for
.


Answer:
I have no idea
Step-by-step explanation: