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2 years ago

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Vector u has its initial point at (21,12) and its terminal point at (19,-8). Vector v has a direction opposite that of u, whose

magnitude is five times the magnitude of v. Which is the correct form of vector v expressed as a linear combination of the unit vectors I and J

1 answer:

agasfer [191]2 years ago

7 0

Step-by-step explanation:

517÷4685568π√7%+66×74367

You might be interested in

Through (4,-4) ; perpendicular to 6y=x-12

BARSIC [14]

y = mx + b

m = slope and b = y-intercept

We can arrange 6y = x - 12 in the form of y = mx + b

6y = x - 12

y = 1/6(x) - 2

Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.

Negative reciprocal of 1/6 is -6.

The equation for the perpendicular line is

y = -6x + b

To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates

-4 = -6(4) + b

b = -4 + 6(4)

b = -4 + 24

b = 20

So the equation for the perpendicular line is y = -6x + 20

3 0

3 years ago

The perimeter of the triangle

Illusion [34]

Area=228 feet sqa.
Length=12 ft.
Breadth=(228/12) ft.
=19 ft.
Perimeter=2(12+19) ft.
=2×31 ft.
=62 ft.

HOPE IT HELPS UH!!☺️☺️

8 0

3 years ago

A coin is to be spun 25 times. Let x be the number of spins that result in heads (H). Consider the following rule for deciding w

larisa [96]

Answer:

0.0433

Step-by-step explanation:

Since we have a fixed number of trials (N = 25) and the probability of getting heads is always p = 0.05, we are going to treat this as a binomial distribution.

Using a binomial probability calculator, we find that the probability of obtaining heads from 8 to 17 times is 0.9567 given that the con is fair. The probability of obtaining any other value given that the coin is fair is going to be:

1 - 0.9567 = 0.0433

Since we are going to conclude that the coin is baised if either x<8 or x>17, the probability of judging the coin to be baised when it is actually fair is 4.33%

5 0

3 years ago

uppose that Mary's utility function is U(W) = W0.5, where W is wealth. She has an initial wealth of $100. How much of a risk

Stels [109]

Note that $U(W) = W^{0.5}$

Answer:

Mary's risk premium is $0.9375

Step-by-step explanation:

Mary's utility function, $U(W) = W^{0.5}$

Mary's initial wealth = $100

The gamble has a 50% probability of raising her wealth to $115 and a 50% probability of lowering it to $77

Expected wealth of Mary, $E_w$

$E_{w}$ = (0.5 * $115) + (0.5 * $77)

$E_{w}$ = 57.5 + 38.5

$E_{w}$ = $96

The expected value of Mary's wealth is $96

Calculate the expected utility (EU) of Mary:-

$E_u = [0.5 * U(115)] + [0.5 * U(77)]\\E_u = [0.5 * 115^{0.5}] + [0.5 * 77^{0.5}]\\E_u = 5.36 + 4.39\\E_u = \$ 9.75$

The expected utility of Mary is $9.75

Mary will be willing to pay an amount P as risk premium to avoid taking the risk, where

U(EW - P) is equal to Mary's expected utility from the risky gamble.

U(EW - P) = EU

U(94 - P) = 9.63

Square root (94 - P) = 9.63

If Mary's risk premium is P, the expected utility will be given by the formula:

$E_{u} = U(E_{w} - P)\\E_{u} = U(96 - P)\\E_u = (96 - P)^{0.5}\\(E_u)^2 = 96 - P\\ 9.75^2 = 96 - P\\95.0625 = 96 - P\\P = 96 - 95.0625\\P = 0.9375$

Mary's risk premium is $0.9375

7 0

2 years ago

Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago