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3 years ago

Anyone know the answer to this?

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:

-3 plus/minus square root 17 over 4

Step-by-step explanation:

2x squared = -3x + 1 is the same as 2x squared + 3x -1

a=2 b=3 c=-1

sub those into the formula and you get -3 plus/minus square root of 9 + 8 over 2×2

and then you simplify

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Given m||n, find the value of x. (9x-5)(6x+20)

xxTIMURxx [149]

Answer:

5/9 & -10/3

Step-by-step explanation:

Set each to 0 and solve:

9x-5 = 0

9x=5

x=5/9

6x+20=0

6x=-20

x=-20/6

x= -10/3 or -3 1/3

7 0

3 years ago

Evaluate the following numerical expressions. 6 + 3.4 =

avanturin [10]

Answer:

6+3.4=9.4

Step-by-step explanation:

the 6 and the 3 add normally, and you just add 0.4 in the decimal place

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3 years ago

Let U = {0,1,2,3,4,5,6,7,8,9}

ELEN [110]

5 I think I'm not surreeeeee

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3 years ago

Select the correct answer.

zhannawk [14.2K]

Answer:

It is B. 15 because the formula for this is 2 (l+w) 15+6=21 21*2=42

4 0

3 years ago

You observe a portfolio for five years and determine that its average annual return is 13% and the standard deviation of its ret

horrorfan [7]

Answer:

There is a 95% probability that the portfolio would not loose more than 30% of its value.

Step-by-step explanation:

The confidence interval for proportions (p) is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

$\hat p = 0.13\\\sqrt{\frac{\hat p(1-\hat p}{n}} =0.21$

For 95% confidence level the critical value of z is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

The 95% confidence interval for average annual return is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.13\pm 1.96\times0.21\\=0.13\pm 0.4116\\=(-0.2816, 0.5416)\\\approx(-28\%, 54\%)$

The lower limit of the 95% confidence interval is -28%.

This implies that the portfolio would not loose more than 28% of its value.

Thus, there is a 95% probability that the portfolio would not loose more than 30% of its value.

6 0

3 years ago