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3 years ago

7.5% of 140 is what number?

Mathematics

2 answers:

posledela3 years ago

5 0

Answer:

10.5

Step-by-step explanation:

0.075*140=10.5

of= *

grigory [225]3 years ago

3 0

Answer:

10.5

Step-by-step explanation:

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3 years ago

What is 4/5+1/4 ? In fraction form.

snow_lady [41]

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3 years ago

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2 years ago

Determine the value of c that will result in a perfect square trinomial. <br> w^2+6w+ c =130+c

Genrish500 [490]

Answer:

The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

Step-by-step explanation:

We need to determine the value of c that will result in a perfect square trinomial.

$w^2+6w+ c =130+c$

Perfect square trinomial are of form: $a^2+2ab+b^2=(a+b)^2$

Now, the equation given is:

$w^2+6w+ c =130+c$

Looking at the term 6w, we can write it as 2(w)(3)

We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2

So, we will be adding (3)^2 on both sides

$w^2+6w+ c=130+c\\w^2+2(w)(3)+ (3)^2 =130+(3)^2\\The\:left\:side\:becomes: a^2+2ab+b^2\\We\:can\:write\:it\:as: (a+b)^2\\We\:have\:a=w\: and\: b=3\\(w+3)^2=130+9\\(w+3)^2=139$

So, The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

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3 years ago

Find the vertex, focus, directrix, and focal width of the parabola. (5 points)

Anarel [89]

$\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})$

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.

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3 years ago