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Evgesh-ka [11]
3 years ago
14

7.5% of 140 is what number?

Mathematics
2 answers:
posledela3 years ago
5 0

Answer:

10.5

Step-by-step explanation:

0.075*140=10.5

of= *

grigory [225]3 years ago
3 0

Answer:

10.5

Step-by-step explanation:

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A,C,D,E, & H are all examples or ways of plagiarism!
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What is 4/5+1/4 ? In fraction form.
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To answer this question you must make a come factor between the 2 fractions I believe the easiest way to do this is multiply the denominator or bottom number by the other one so 4*5 and 5*4 and what you do to the denominator you must do to the numerator so you would have to do 4*4 and 4*5 for the first fraction to get 16/20 and repeat on the other side 1*5 and 4*5 or 5/20 so the to fractions are 16/20+5/20 then add just the numerators 16+5=21 or 21/20 and simplify to 1/20
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How do you estimate the mean? please help
skelet666 [1.2K]

Answer:

move the anomalous results

numbers that don go or are not similar to the other numbers

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8 0
2 years ago
Determine the value of c that will result in a perfect square trinomial. <br> w^2+6w+ c =130+c
Genrish500 [490]

Answer:

The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: (w+3)^2=139

Step-by-step explanation:

We need to determine the value  of c that will result in a perfect square trinomial.

w^2+6w+ c =130+c

Perfect square trinomial are of form: a^2+2ab+b^2=(a+b)^2

Now, the equation given is:

w^2+6w+ c =130+c

Looking at the term 6w, we can write it as 2(w)(3)

We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2

So, we will be adding (3)^2 on both sides

w^2+6w+ c=130+c\\w^2+2(w)(3)+ (3)^2 =130+(3)^2\\The\:left\:side\:becomes: a^2+2ab+b^2\\We\:can\:write\:it\:as: (a+b)^2\\We\:have\:a=w\: and\: b=3\\(w+3)^2=130+9\\(w+3)^2=139

So, The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: (w+3)^2=139

3 0
3 years ago
Find the vertex, focus, directrix, and focal width of the parabola. (5 points)
Anarel [89]

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this  case, is simply yeap, you guessed it, 20.

8 0
3 years ago
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