A,C,D,E, & H are all examples or ways of plagiarism!
To answer this question you must make a come factor between the 2 fractions I believe the easiest way to do this is multiply the denominator or bottom number by the other one so 4*5 and 5*4 and what you do to the denominator you must do to the numerator so you would have to do 4*4 and 4*5 for the first fraction to get 16/20 and repeat on the other side 1*5 and 4*5 or 5/20 so the to fractions are 16/20+5/20 then add just the numerators 16+5=21 or 21/20 and simplify to 1/20
Answer:
move the anomalous results
numbers that don go or are not similar to the other numbers
add the numbers and divide by how many numbers you added
Answer:
The value of c that will result in a perfect square trinomial is (3)^2 or 9
The perfect square trinomial is: 
Step-by-step explanation:
We need to determine the value of c that will result in a perfect square trinomial.

Perfect square trinomial are of form: 
Now, the equation given is:

Looking at the term 6w, we can write it as 2(w)(3)
We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2
So, we will be adding (3)^2 on both sides

So, The value of c that will result in a perfect square trinomial is (3)^2 or 9
The perfect square trinomial is: 
![\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvertical%20parabola%20vertex%20form%20with%20focus%20point%20distance%7D%20%5C%5C%5C%5C%204p%28y-%20k%29%3D%28x-%20h%29%5E2%20%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5Cqquad%20%5Cstackrel%7Bfocus~point%7D%7B%28h%2Ck%2Bp%29%7D%5Cqquad%20%5Cstackrel%7Bdirectrix%7D%7By%3Dk-p%7D%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%20%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22p%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22p%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,
vertex is at (0,0)
the focus point is "p" or 5 units down from there, namely at (0, -5)
the directrix is "p" units on the opposite direction, up, namely at y = 5
the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.