The starting number is 245.So it’s already pretty deep in the water,then it goes down 83 feet MORE.so that’s 245+83=328 feet. Then the submarine goes UP 103 feet from that point,so 328-103=225 feet,so its closer to the surface than at the beginning(245ft)
Answer:
Given - a = 4
b = 9
c = 1
To find - Value of equation
Solution -
3b ÷ c^1 - a
Putting the value of a,b and c in the equation
3(9) ÷ (1)^1 - 4
27 ÷ 1 - 4
27 ÷ (-3)
27 × (1 /(-3)
27/(-3)
(-9)
A=(3.14)(12.5)^2
A=(3.14)(156.25)
A=490.625 ft squared
First find the gradient of line AB
14--3/7--10
17/17 = 1
As CD is perpendicular to AB take the negative reciprocal of the gradient to AB to find gradient of CD
Gradient of CD = -1
to find y intercept use points given
12=(-1 x 5) +c
17 = c
C is the y intercept so for question 1 the answer is 3
for the second question just plug values into the equation and see if you get the right y value
Here the only number that works is -2
for question 2
the answer is 2
Answer:
The answer to your question is letter C
Step-by-step explanation:
With zeros 1, 2 and -5
Process
1.- Equal the zeros to x
x₁ = 1 x₂ = 2 x₃ = - 5
x₁ - 1 = 0 x₂ - 2 = 0 x₃ + 5 = 0
2.- Write the roots as a product
(x - 1)(x - 2)(x + 5)= 0
3.- Multiply the zeros
(x - 1)(x - 2) = x² - 2x - x + 2
Simplify = x² - 3x + 2
(x + 5)(x² - 3x + 2) = x³ - 3x² + 2x + 5x² - 15x + 10
Simplify like terms and result
= x³ + 2x² - 13x + 10
