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3 years ago

Prove the two triangles congruent. sas sss asa aas hl not congruent

Mathematics

1 answer:

ivanzaharov [21]3 years ago

6 0

Answer:

SAS because there congruent and each side has the same degree

Step-by-step explanation:

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Aaron says that all

Softa [21]

Answer:

Step-by-step explanation:

Look at the figure attached below, we know that the area of the cone is the sum of area of circle part and cone part of the figure.

to find the surface area of the cone, first measure the radius of the base and find the area of the circle part by formula $\pi r^2$ . Then measure the side (slant height) length of the cone part and find the area of the cone part by the formula $\pi rl$ .

Now the surface area of the cone is circumference of the circle plus area of the cone part.

i.e. $surface\ Area\ of\ the\ cone=\pi r^{2}+\pi rl$

From the above discussion we concluded that surface area of the cone does not depend only on the circumference of the base but also we need side length of the cone part as well thus all cones with a base circumference of 8 inches will not have the same surface area.

5 0

3 years ago

Look at the figure which step should be taken next to construct a line parallel to AB

FinnZ [79.3K]

My answer is the 2nd option.

Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.

Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB.

8 0

3 years ago

The perimeter of a rectangle is 66 feet. The width is 15 ft less than 1/2 the length. Find the dimensions of the figure

lianna [129]

The length is 32 and the width is 1. 32÷2 is 16. 16-15 is 1. 32+32+1+1 is 66

8 0

3 years ago

Kindly solve this question 6 too !!

Shkiper50 [21]

Answer:

$x=1$

Step-by-step explanation:

$~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1$

7 0

2 years ago

Whats the answer for this 4b²+20b+25

WITCHER [35]

4b²+20b+25=0

Divide everything by 4

b²+5b+ 6.25=0

use the quadratic formula
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2

7 0

3 years ago