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kiruha [24]
3 years ago
14

Which angles are supplementary to 24? Select all that apply.​

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

<2, <3, <6, <7

Step-by-step explanation:

Supplementary to <4 means that, <4 and that angle equals 180. So we will move angle by angle.

<1 = Is not supplementary because both are virtually opposite angle and virtually opposite angles are equal.

<2 = Is supplementary angle because it is a vertical linear pair with <4.

<3 = Is supplementary angle because it is horizontal linear pair with <4

<5 = Is not supplementary angle because they are alternate interior angles and alternate angles are equal.

<6 = Is supplementary because angles on the same side and same interior/exterior are supplementary. (By interior/exterior, I meant that they have to be either interior or exterior. No both)You can also use the reason that 6 and 2 are corresponding angles, and corresponding angles are equal. So, if 2 is supplementary to 4, then 6 is also supplementary to 4. I think the latter is better than the first.

<7 = Is supplementary because it is vertically opposite to 6 and 6 is supplementary, so 7 is also supplementary.

<8 = Not supplementary. Because 4 and 8 are corresponding angles and corresponding angles are not equal. And also 8 is equal to 5. And 5 is not supplementary to 4. That means 8 is also not.

Ugh... I really hope u understand, and don't think that I am blabbering.

Thank You

Please mark me as the brainliest

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katen-ka-za [31]

Question # 13

Answer:

The required equation for the given function is <em>y = 4sin(x/2+2π/3) -2 , as shown attached graph diagram.</em>

<em>Step-by-step explanation: </em>

As the general sine function is given by

y=asin(bx+c)+d.......[A]

  • amplitude = a
  • period = 2π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • amplitude = a = 4
  • period = 4π
  • phase shift = -4π/3
  • Vertical shift = d = -2

As  

period = 2π ÷ b  

b = 2π/period

b = 2π/4π ∵ period = 4π

b = 1/2  

Also

Phase shift = -c/b

-4π/3 = -c/b ∵ phase shift = -4π/3

4π/3 = c/b  

c = b × 4π/3  

c = 1/2 × 4π/3  

c = 4π/6  

c = 2π/3

So, putting Amplitude ⇒ a = 4, Vertical shift ⇒ d = -2, b = 1/2 ,  

and c = 2π/3 in Equation [A] would bring us the required equation for the given function.

y=asin(bx+c)+d

y = 4sin(x/2+2π/3)+(-2)

y = 4sin(x/2+2π/3) -2            

<em>Note: The graph is also shown in attached diagram.</em>

                                             Question # 14

<em>Answer:</em>

The required equation for the given function is y = cot(x+π/3)+2, as shown in attached graph diagram.

<em>Step-by-step explanation: </em>

As the general cotangent function is given by

y=acot(bx+c)+d.......[A]

  • amplitude = a
  • period = π ÷ b
  • Phase shift = -c ÷ b
  • Vertical shift = d

As in the question,  

  • period = π
  • phase shift = -π/3
  • Vertical shift = d = 2

As  

period = π ÷ b  

b = π/period

b = π/π ∵ period = 4π

b = 1  

Also

Phase shift = -c/b

-π/3 = -c/b ∵ phase shift = -π/3

π/3 = c/b  

c = b × π/3  

c = 1 × π/3  

c = π/3

So, putting vertical shift ⇒ d = 2, b = 1 and   c = π/3 in Equation [A] would bring us the required equation for the given function.

y=acot(bx+c)+d

y = cot(x+π/3)+2

<em>Note: The graph is also shown in attached diagram.</em>

Keywords: amplitude, period , phase shift , vertical shift

Learn more about trigonometric functions of equations from brainly.com/question/2643311

#learnwithBrainly

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