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soldier1979 [14.2K]
3 years ago
7

Write a quadratic function in standard form whose graph passes through (4,0) and (6,0)

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
8 0

Answer:

f(x) = x² - 10x + 24

Step-by-step explanation:

The quadratic function has a graph that passes through the points (4,0) and (6,0).

Therefore, the graph has two x-intercepts at x = 4 and x = 6 and those are the roots of the equation.

So, (x - 4) and (x - 6) are two factors of the quadratic equation.

Then we can write the equation as  

f(x) = (x - 4)(x - 6)

⇒ f(x) = x² - 4x - 6x + 24

⇒ f(x) = x² - 10x + 24

Hence, this is the required quadratic function in standard form. (Answer)

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Find the value of x that will make a||b help ?
nydimaria [60]

Answer:

x=30

Step-by-step explanation:

Find the value of x that will make A and B parallel

For A & B to be parallel, the interior angles must be supplementary, i.e.

4x+2x = 180

6x=180

x=30

When x=30, the interior angles are 120 and 60 which are supplementary.

4 0
3 years ago
Is -¼ + 2 ¼y + 2 - y equivalent to y + 2 ?
Juliette [100K]

Answer: No

Step-by-step explanation:

-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2

(-\frac{1}{4}+2)+(2\frac{1}{4}y-y)=y+2\\

(\frac{(-1)+(4)(2)}{4})+(\frac{9}{4}y-y)=y+2

(\frac{-1+8}{4})+(\frac{(9)(1)-(4)(1)}{4} )y=y+2

(\frac{7}{4})+(\frac{9-4}{4} )y=y+2

(\frac{7}{4})+(\frac{5}{4})y=y+2

5 0
3 years ago
In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 42.9%. the differen
fenix001 [56]
Let
 x = number of common cars
 y = number of suvs
 we can write the following system of equations
 x-y = 12
 x = 1.429y
 Solving the system we have
 x-y = 12
 1.429y-y = 12
 and (1,429-1) = 12
 y = (12) / (1,429-1) = 27.97202797
 then,
 x = 1429 * (27.97202797)
 x = 39.97202797
 answer
 The number of suvs in the parking lot is 28
6 0
3 years ago
The range of the data: 7, 10, 30, 16, 8, 5, 3, 18, 35, and 1 tell the answer only
Nikitich [7]
It is 32 because highest number subtracted by lowest
3 0
3 years ago
Read 2 more answers
ANSWER THIS AND ILL LOVE YOU <br><br> find angles FAB and BAC
jeyben [28]

Answer:

m<FAB = 75°

m<BAC = 105°

Step-by-step explanation:

First, find the value of x.

(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)

Solve for x

13x - 3 = 3x + 2 + 55

13x - 3 = 3x + 57

Collect like terms

13x - 3x = 57 + 3

10x = 60

Divide both sides by 10

x = 6

✔️m<FAB = 13x - 3

Plug in the value of x

m<FAB = 13(6) - 3 = 78 - 3

m<FAB = 75°

✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)

m<BAC = 180 - 75 (substitution)

m<BAC = 105°

4 0
2 years ago
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