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3 years ago

A box of spaghetti weighs 1 pound. Lindsay

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer:

yes she'll be to make another meal

Step-by-step explanation:

1 pound = 16 oz

lindsay cooked nine ounces

16 - 9

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Can someone explain just 17-28??

Tatiana [17]

Answer:

you solve these by plugging the numbers into pythagorean theorem which is

a^2 + b^2 = c^2 (a squared plus b squared equal c squared)

C is the hypotenuse which is the longest side across from the right angel (assuming all these problems are for right triangles)

so 17 would be 9.5^2 + 3.8^2 = c^2

So 90.25 + 14.44 = c^2

104.69=c^2

Then to solve for c take the square root of each side and get

10.23=c

To do the other ones where a or b doesn’t have a value, it’s almost the same but you just have to plug in the variables in different places and solve it

Step-by-step explanation:

8 0

3 years ago

Estimate each product. 2/9 of 88

kakasveta [241]

<span>19.55
</span>That's what I have gotten.

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3 years ago

Suppose θ is an angle in the standard position whose terminal side is in Quadrant IV and cot θ= -6/7 . Find the exact values of

Llana [10]

Answer:

Part 1) $csc(\theta)=-\frac{\sqrt{85}}{7}$

Part 2) $sin(\theta)=-\frac{7}{\sqrt{85}}$ or $sin(\theta)=-\frac{7\sqrt{85}}{85}$

Part 3) $tan(\theta)=-\frac{7}{6}$

Part 4) $cos(\theta)=\frac{6}{\sqrt{85}}$ or $cos(\theta)=\frac{6\sqrt{85}}{85}$

Part 5) $sec(\theta)=\frac{\sqrt{85}}{6}$

Step-by-step explanation:

we know that

The angle theta lie on the IV Quadrant

sin(θ) is negative

cos(θ) is positive

tan(θ) is negative

sec(θ) is positive

csc(θ) is negative

step 1

Find the value of csc(θ)

we know that

$1+cot^{2}(\theta)=csc^{2}(\theta)$

we have

$cot(\theta)=-\frac{6}{7}$

substitute

$1+(-\frac{6}{7})^{2}=csc^{2}(\theta)$

$1+\frac{36}{49}=csc^{2}(\theta)$

$\frac{85}{49}=csc^{2}(\theta)$ rewrite

$csc(\theta)=-\frac{\sqrt{85}}{7}$ ----> remember that is negative

step 2

Find the value of sin(θ)

we know that

$csc(\theta)=\frac{1}{sin(\theta)}$

we have

$csc(\theta)=-\frac{\sqrt{85}}{7}$

therefore

$sin(\theta)=-\frac{7}{\sqrt{85}}$

$sin(\theta)=-\frac{7\sqrt{85}}{85}$

step 3

Find the value of tan(θ)

we know that

$tan(\theta)=\frac{1}{cot(\theta)}$

we have

$cot(\theta)=-\frac{6}{7}$

therefore

$tan(\theta)=-\frac{7}{6}$

step 4

Find the value of cos(θ)

we know that

$sin^{2}(\theta)+cos^{2}(\theta)=1$

we have

$sin(\theta)=-\frac{7}{\sqrt{85}}$

substitute

$(-\frac{7}{\sqrt{85}})^{2}+cos^{2}(\theta)=1$

$\frac{49}{85}+cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{49}{85}$

$cos^{2}(\theta)=\frac{36}{85}$

$cos(\theta)=\frac{6}{\sqrt{85}}$ ------> the cosine is positive

$cos(\theta)=\frac{6\sqrt{85}}{85}$

step 5

Find the value of sec(θ)

we know that

$sec(\theta)=\frac{1}{cos(\theta)}$

we have

$cos(\theta)=\frac{6}{\sqrt{85}}$

therefore

$sec(\theta)=\frac{\sqrt{85}}{6}$ ----> is positive

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4 years ago

Please help WILL MARK BRAINLIEST! (random answers will be reported)

bixtya [17]

Answer:

Step-by-step explanation:

The formula for volume of a cylinder is V = π $r^{2}$ h. We replace r with the radius (to find it just divide the diameter by 2), which is 2.5. Hope this helped!! :]

6 0

3 years ago

Read 2 more answers

Find the solution for the system of linear equations by substitution: y = 3x + 4 and y = x + 2.

ludmilkaskok [199]

Answer:

Step-by-step explanation:

y = 3x + 4, and

y = x + 2

------------------

Use the vale of y in the 2nd equation in the first:

y = 3x + 4

x + 2 = 3x + 4

-2x = 2

x = -1

Use this value of x (-1) in either equation to find y:

y = x + 2

y = -1 + 2

y = 1

==========

(-1,1)

See attached graph.

3 0

3 years ago