Since one atmosphere is 29.9213 inches of mercury, we can simply find this by taking 29.9213 and multiplying that by 1.24. You end up with 37.102412 inches of mercury. I hope this helps you out, and good luck on the rest of your homework.
Answer:
0.295 L
Explanation:
It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:
" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "
Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.
To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂
Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.
- 47.2 mL * 150 mM = 24.0 mM * V₂
And <u>converting into L </u>becomes:
- 295 mL *
= 0.295 L
Answer:
The first person to go to the moon
Explanation:
Neil Armstrong was the first person !
heres more info on NASAs page!
https://www.nasa.gov/audience/forstudents/k-4/stories/first-person-on-moon.html
Explanation:
Ca3(PO4)2 1 mole has 310.2 g
Ca3(PO4)2 4.3 × 10^-4 moles has 4.3 × 10^-4 × 310.2
= 1,333.86 × 10^-4
= 1.334 × 10^-1
OR 0.1334 g