The ph decreases. W<span>hen you blow out, you exhale carbon dioxide gas, which is soluble in water. The dissolved CO2 (known as carbonic acid) is acidic, and therefore the pH will fall, but not significantly. You will never be able to measurably determine that there is a difference....at least not with pH testing strips. However, if you put a very small amount (just a few grains) of sodium carbonate in about 100 mL of water and add a drop of phenolthalein, the solution will turn pink, indicating that it is a base (a very weak one, about pH 8) Then, if you blow bubbles into the water with a straw for about 2 minutes, the solution will go from pink to clear, indicating that it is no longer a base. Your breath has neutralized the base.</span>
The question is incomplete, the complete question is;
An alcohol thermometer makes use of alcohol's changing _______ in order to measure temperature. As the temperature goes up, the alcohol contained in the thermometer increases in volume, filling more of the thermometer's tube.
A.
mass
B.
state
C.
chemical composition
D.
density
Answer:
D.
density
Explanation:
Every kind of thermometer makes use of a change in a particular physical property of a substance as a measure of temperature. It must be a property that changes with temperature.
Density of a substance changes with temperature. Even though the mass of alcohol in glass remains constant, but its volume increases or decreases with change in temperature leading to a change in volume and consequently a change in density of the alcohol in glass. This change is used as a measure of the change in temperature.
Answer:
it is ammonia nitro oxide
Answer:
pH = 11.7
Explanation:
<u>Given:</u>
[OH-] = 0.00500 M
<u>To determine:</u>
pH of the solution
<u>Explanation:</u>
pH refers to the H+ ion concentration in a given solution whereas pOH indicates the OH- ion concentration.
pH and pOH are related by the following equation:
Here:
![pH = -log[H+]\\\\pOH = -log[OH-]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%2B%5D%5C%5C%5C%5CpOH%20%3D%20-log%5BOH-%5D)
When OH- = 0.00500 M
Based on equation(1):
