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matrenka [14]
3 years ago
8

What state of matter has a definite shape and volume.

Chemistry
1 answer:
anastassius [24]3 years ago
3 0

Solids have a definite shape and volume. They are always the same shape no matter what they are contained in; their volume is also the same because they don't change unless you add or take away from it.

____________________________________________________________

Liquids have an indefinite shape but definite volume. They expand to fill out the space they are contained in, but their volume doesn't change unless you take out or add more of the liquid.

Gases have an indefinite shape and volume. Gases expand to fill out the space they are in and also don't have a clear shape because they are not always in one form.

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Explain the different between a molecule and a compound.
nevsk [136]

Answer:

-A molecule is the smallesr part is compound whereas a compound is the combination of two or more atoms in a fixed proportion by wiehgt.

- A glass of water is an example of compound but a small portion of water can be called molecule.

5 0
3 years ago
When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb
aliya0001 [1]

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately <u>-716.2 kJ</u>

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat  capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

  • C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = \dfrac{3.93 \, g}{90.07 \, g/mol} = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid  = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

  • \Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx  -716.2

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ <u>-716.2 kJ</u>.

Learn more here:

brainly.com/question/13185938

5 0
2 years ago
Uranium – 235 has a half-life of 713 million years. Would uranium – 235 or carbon – 14 be more useful for dating Cambrian time e
kenny6666 [7]
Uranium-235 would be more useful for dating in Cambrian time because Cambrian time was 540 million years ago while the half life of carbon-14 is only 5,730 years
Hope this helps
6 0
3 years ago
Write down 5 examples of science in your every day life
DiKsa [7]

Ur cars exhaust tank ur freezer ur toaster ur microwave ur shower
6 0
3 years ago
Read 2 more answers
20 points be right this is my final!!!
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What else will happen.
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