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Vilka [71]
3 years ago
8

Which type of bond is generally considered "risk-free" since the issuer of the bond has the ability to print money to meet their

obligations? Corporate Bond Municipal Bond U.S. Treasury Bond Bail Bond
Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

U.S. Treasury Bond

Step-by-step explanation:

A bond is a debt instrument.

the US government cannot default on a bond. thus government bonds are considered riskless. this is because the government can print money with the central bank to pay debt obligations

other debt issuers cannot print money to pay debt obligations. thus, they are not riskless

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Evaluate the expression
Vera_Pavlovna [14]

Answer:

C) 960

Step-by-step explanation:

Let's expand the factorial.

n! = 1*2*3*4*...n

6! = 1*2*3*4*5*6

3!= 1*2*3

The given expression \frac{8. 6!}{3!} \\

= \frac{8.1.2.3.4.5.6 }{1.2.3}

Canceling out the common terms, we get

= \frac{8.4.5.6}{1} \\

= 8.4.5.6                     [here . represents multiplication]

= 960

Answer: C) 960

Thank you.

7 0
4 years ago
Read 2 more answers
The useful life of a radial tire is normally distributed with a mean of 30,000 miles and a standard deviation of 5000 miles. The
otez555 [7]

Answer:

  empirical rule: 81.5%

  table or calculator: 81.9%

Step-by-step explanation:

The lower limit of the life range of interest has a z-score of ...

  z = (x -μ)/σ = (20,000 -30,000)/5,000 = -2

The upper limit has a z-score of ...

  z = (35,000 -30,000)/5,000 = 1

<u>Empirical rule solution</u>

The empirical rule tells you that 95% of the distribution lies within 2 standard deviations of the mean, so (100% -95%)/2 = 2.5% lie below z = -2. It also tells you 68% lie within 1 standard deviation of the mean, so (100% -68%)/2 = 16% lie above z = 1.

The fraction that lies within -2 to 1 standard deviations of the means is thus ...

  (100% -2.5% -16%) = 81.5%

The probability the tire has a life in the desired range is about 81.5%.

__

<u>Calculator solution</u>

A probability calculator for the Normal distribution tells you that ...

  P(-2 < z < 1) ≈ 0.8185946

The probability the tire has a life in the desired range is about 81.9%.

6 0
3 years ago
a honda element with a dealer invoice price is $19,700 was retail price at $23,000. How much is the approximate percent markup b
andrew11 [14]
17% of 19,700 = 3349.  So if you add 3349 to 19,700 you get 23,049. So it sounds like it's around a 16-17% markup. 
4 0
4 years ago
10% of ________ is 7<br> 25% of ________ is 6
GrogVix [38]

Answer:

I got

10% of 70 is 7

5 0
3 years ago
Read 2 more answers
Both please please :)…….,,,,,
denis23 [38]

Answer:

Step-by-step explanation:

One - 44

88% of 50 is 44

Two - 55296 60,000-4%-4%=55296

3 0
4 years ago
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