Consider this option:
1. the equation of given line is y=-x-3 (it is easy to find it using points (0;-3)&(-3;0)).
2. according to the equation of line: y≥-x-3
Answer:
AB // CD and AD // BC, then ABCD is a parallelogram
Step-by-step explanation:
Step 2: Show AD // BC
A = (-3 , 3) and D = (0 , 0)
Find the slope of AD

B = (2 , 5) and C = (5 , 2)

The slope of AD = the slope of BC
So AD // BC because they have the same slope
Step 3:
Each two opposite sides are parallel in quadrilateral ABCD
So the quadrilateral is a parallelogram
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
First add 90 to both sides) -mk>85+90simplify 85+90 to 175) -mk>175divide both sides by K) -m>175/kmultiply both sides by -1) m<-175/k
YOUR ANSWER IS
M<-175/K
hope l helped today l was stuck on the same question doing part 2 of alg exam , and l came through your question l hope it's not too late :)