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4 years ago

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Lamont measured a city park and made a scale drawing. In real life, the soccer field is 70 meters wide. It is 175 millimeters wi

de in the drawing. What scale did Lamont use for the drawing?
5 millimeters :___meters

1 answer:

Alekssandra [29.7K]4 years ago

6 0

Answer: Your complete answer is - 105

Step-by-step explanation: subtract 70 from 175 and your answer is 105

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I NEED HELP PLZZ :((<br><br> 5/2 ÷ 3/4<br> pls help me solve this

galina1969 [7]

Answer:

3 1/3 Because When we divide two fractions, such as 5/2 ÷ 3/4, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.

Step-by-step explanation:

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Suppose You want to but three loaves of bread that cost $1.50 each and a jar of grape jelly that costs $4.A jar of Peanut Butter

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You want 3 loaves of bread, at $1.50 a piece and a jar of jelly, at $4. So set up the equation 3(1.5)+1(4). You don't want peanut butter so that's unnecessary information. Your total is $8.50, so subtract that from 10, you get 1.5. You will have $1.50 left over.

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What is the equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y =

Zepler [3.9K]

The equation of the line that passes through the point (5,4) and is perpendicular to the line whose equation is 2x + y = 3 in standard form is x - 2y = - 3

<u>Solution:</u>

Given, line equation is 2x + y = 3

2x + y – 3 = 0 ----- eqn (1)

We have to find a line that is perpendicular to 2x + y – 3 = 0 and passing through (5, 4).

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{1}=-2$

$\text { Slope of a line } \times \text { slope of perpendicular line }=-1$

$\begin{array}{l}{-2 \times \text { slope of perpendicular line }=-1} \\\\ {\text { Slope of perpendicular line }=-1 \times \frac{1}{-2}=\frac{1}{2}}\end{array}$

Now, slope of our required line = 1/2 and it passes through (5, 4)

<em><u>The point slope form is given as:</u></em>

$y-y_{1}=m\left(x-x_{1}\right)$

$\text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }$

$\text { Here in our problem, } \mathrm{m}=\frac{1}{2}, \text { and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(5,4)$

$y-4=\frac{1}{2}(x-5)$

<em><u>Now let us convert to standard form:</u></em>

The standard form of a line is just another way of writing the equation of a line.

The standard form of an equation is Ax + By = C. In this kind of equation, x and y are variables and A, B, and C are integers.

2(y – 4) = 1(x - 5)

2y – 8 = x – 5

x – 2y - 5 + 8 = 0

x - 2y + 3 = 0

x - 2y = - 3

Hence, the line equation in standard form is x - 2y = - 3

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4 years ago