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Ksivusya [100]
3 years ago
7

Which ordered pair in the form (x,y) is a solution of this equation?

Mathematics
1 answer:
qwelly [4]3 years ago
7 0
D
7•4 =28, -5•0 =0... 28+0=28
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Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)? ​
timofeeve [1]

Answer:

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Step-by-step explanation:

THIS IS THE COMPLETE QUESTION

In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?

SOLUTION

✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.

Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)

Within the 1hour minutes, the hand can move with complete cycle of 2π radians

Then At time t= 45minutes

Angle through the circle at 45 minutes= 45/60 ×2π radians

= 3π/2 radians

And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians

For t=45 minutes

Then 1/12 × 2π ×45/60

= π/8 radians

Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.

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