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ratelena [41]
3 years ago
10

Prove the following identities : i) tan a + cot a = cosec a sec a​

Mathematics
1 answer:
inysia [295]3 years ago
7 0

Step-by-step explanation:

\tan \alpha + \cot\alpha = \dfrac{\sin \alpha}{\cos \alpha} +\dfrac{\cos \alpha}{\sin \alpha}

=\dfrac{\sin^2\alpha + \cos^2\alpha}{\sin\alpha\cos\alpha}=\dfrac{1}{\sin\alpha\cos\alpha}

=\left(\dfrac{1}{\sin\alpha}\right)\!\left(\dfrac{1}{\cos\alpha}\right)=\csc \alpha \sec\alpha

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in the diagram below, AB and BC are tangent to O. Which equation could be solved to find y, the measure of ADC
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Answer:

A

Step-by-step explanation:

∠ABC is formed by 2 tangents to the circle and is measured as

∠ABC = \frac{1}{2} (m  arc ADC - m arc AC ), that is

\frac{1}{2} (y - 119) = 61 → A

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Paaaa hellllpppp po with solution po sana​
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<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

  • If something is being added to x, subtract it from both sides.
  • If something is being subtracted from x, add it on both sides.
  • Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

5x+7=15

Because 7 is being added to x, subtract it from both sides:

5x+7-7=15-7\\5x=8

Because x is being multiplied by 5, divide both sides by 5:

\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}

Therefore. x=\dfrac{8}{5}.

<h3>Question 2</h3>

7x+4=5x-18

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

7x+4-5x=5x-18-5x\\2x+4=-18

To isolate x, subtract 4 from both sides:

2x+4-4=-18-4\\2x=-22

Divide both sides by 2:

\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11

Therefore, x=-11.

6 0
2 years ago
Your monthly living expenses are $1500 on an income of $1,650 per month. Your goal is to have an emergency fund of 4 times your
Aneli [31]
For the answer to the question above, your end goal is to have $6,000 total in 12 months. since you have $2400 already you can subtract that from 6,000 leaving you with $3600 over the course of 12 months. since you already put $150 in a month over the course of 12 months you would have $1800 which is only half of the goal of $3600. in order for you to put in $3600, you would have to put an additional 150 in your savings along with your regular 150 making Letter B the answer.
4 0
3 years ago
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In the past, the population proportion of consumers preferring orange juice with no pulp was equation. To test if this populatio
geniusboy [140]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

a) For the null hypothesis,

P = 0.45

For the alternative hypothesis,

P ≠ 0.45

b) For the decision rule, we would reject H0 if 0.1 > p value and accepth H0 if 0.1 < p value

Considering the population proportion, probability of success, p = 0.45

q = probability of failure = 1 - p

q = 1 - 0.45 = 0.55

Considering the sample,

Sample proportion, p = x/n

Where

x = number of success = 52

n = number of samples = 120

p = 52/120 = 0.43

c) We would determine the test statistic which is the z score

z = (p - P)/√pq/n

z = (0.43 - 0.45)/√(0.45 × 0.55)/120 = - 0.44

Recall, population proportion, P = 0.45

The difference between sample proportion and population proportion(P - p) is 0.45 - 0.43 = 0.02

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.45 - 0.02 = 0.43

the p for the right tail is 0.45 + 0.02 = 0.47

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.3336

We would double this area to include the area in the right tail of z = 0.44 Thus

p = 0.3336 × 2 = 0.67

d) Since alpha, 0.1 < than the p value, 0.67, then we would fail to reject the null hypothesis. Therefore, at a 1% level of significance, we do not have enough evidence to reject the​ null hypothesis

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