The delta G for the dissociation is 87,865 joule/kg.
The process is non-spontaneous because the value of Gibbs free energy is positive.
<h3>What is dissociation?</h3>
The breaking up of a compound into a simpler form that can be recombined under other conditions.
Given,
![\bold{2NH_3 (g) = N_2(g) + 3H_2(g)}](https://tex.z-dn.net/?f=%5Cbold%7B2NH_3%20%28g%29%20%3D%20N_2%28g%29%20%2B%203H_2%28g%29%7D)
H = 145 kJ
Delta S = 195 J/k
Determining the G using the following process:
G = H -TS
![\bold{G = (145\times10^3 J) -(293K \times 195 J/K})](https://tex.z-dn.net/?f=%5Cbold%7BG%20%3D%20%28145%5Ctimes10%5E3%20J%29%20-%28293K%20%5Ctimes%20195%20J%2FK%7D%29)
G = 87,865 Joules/K
Thus, the value of Delta G is 87,865 and the process is non-spontaneous.
Learn more about dissociation here:
brainly.com/question/4431132
yooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
We have:
V = 55.0 gallons x 3.78541 = 208 L
P = 16500 kPa
T = 23 + 273.15 = 296.15 K
Part A) From the equation PV =
![\frac{mRT}{M}](https://tex.z-dn.net/?f=%20%5Cfrac%7BmRT%7D%7BM%7D%20)
we get:
mass of O₂ = (16500 kPa x 208 L x 32 g/mol) / (8.314 x 296.15 K)
= 44.6 Kg
Part B) at STP we have:
T = 273.15 K and P = 101.3 kPa
so from PV = mRT / M
V = (44600 x 8.314 x 273.15) / (32 x 101.3)
= 31248 L
Part C) From the equation PV = mRT / M
we get
T = (150 atm x 101.3 kPa / atm x 208L x 32g/mol) / (8.314 x 44600)
= 272.8 K
Part D) we have:
T = 24 + 273.15 K = 297.15 K
so from PV = mRT / M, we get
P = (44600 x 8.314 x 297.15) / (32 x 55)
= 62464 kPa
ANSWER:
2.65 g H2O
Explanation:
6.49g (co2) / 44.009g (co2) x 1 mol (co2) / 1 mol (h2o) x 1 mol (h2o)
=0.147 mol H2O
0.147 mol (H2O) / 1 mol (h2o) x 18.015 g (h2o)
=2.65 g H2O