Answer is: 10 gallons of 3% and 15 gallons of 8% solution.
V₁ + V₂ = 25 gallons.
0,03V₁ + 0,08V₂ = 0,06 · 25 gallons.
V₁ = 25 gallons - V₂.
0,03 · (25 gallons - V₂) + 0,08V₂ = 1,5 gallons.
0,75 gallons - 0,03V₂ + 0,08V₂ = 1,5 gallons.
0,05V₂ = 0,75 gallons.
V₂ = 0,75 gallons / 0,05.
V₂ = 15 gallons.
V₁ = 25 gallons - 15 gallons.
V₁ = 10 gallons.
The answer is C) <span>The sample was broken down by the electric current and formed a new substance that could burn. Therefore, the original liquid is a compound. </span>
Answer:
C₆H₆O₃
Explanation:
Calculation sequence:
% => grams => moles => reduce => empirical Ratio
Molecular multiple = Molecular Mass / Empirical Mass
C: => 57.1% => 57.1 g => 57.1/12 = 4.7583
H: => 4.8% => 4.8 g => 4.8/1 = 4.8000
O: => <u>38.1% => 38.1 g </u>=> 38.1/16 = 2.3813
TTL => 100% 100 g
Reduced Mole values =>
C : H : O => 4.7583/2.3813 : 4.8000/2.3813 : 2.3813/2.3813 => 2 : 2 : 1
∴ empirical formula => C₂H₂O
empirical formula weight => 2C + 2H + 1O = [2(12) + 2(1) + 1(16)] amu = 42 amu
molecular formula weight (given in problem) = 126 g/mole
The molecular formula is a whole number multiple of the empirical formula.
molecular multiple = 126 amu / 42 amu = 3
∴ molecular formula => (C₂H₂O)₃ => C₆H₆O₃
The molar mass of Ca(NO₃)2 is 164 g/mol
<u><em> Explanation</em></u>
Ca(NO₃)2 is made up of Ca , N and O elements
Therefore the molar mass of Ca(NO₃)2 = molar mass of Ca + molar mass of N +molar mass of O
from periodic table the molar mass of Ca is 40 g/mol
for N = 14 g/ mol
for O = 16 g/mol. since they are 3 atoms of O in Ca(NO₃)2 the molar mass = 16 x3 = 48 g/mol
The molar mass of Ca(NO₃)2 = 40 g/mo + [(14 g/mol + 48 g/mol) 2] =164g/mol
Answer:
For a digital scale, the uncertainty is ± 1 in the least significant digit.
Explanation: